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Woo Young Lee Lecture Notes on Operator Theory

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CHAPTER 1.<br />

FREDHOLM THEORY<br />

1.11 Spectral Mapping Theorems<br />

Recall the Calkin algebra B(X)/K(X). The Calkin homomorphism π is defined by<br />

π : B(X) −→ B(X)/K(X)<br />

π(T ) = T + K(X).<br />

Evidently, by the Atkins<strong>on</strong>’s Theorem,<br />

T is Fredholm ⇐⇒ π(T ) is invertible.<br />

Theorem 1.11.1. If T ∈ B(X) and f is analytic in a neighborhood of σ(T ), then<br />

f(σ e (T )) = σ e (f(T ))<br />

Proof. Since f(π(T )) = f(T + K(X)) = f(T ) + K(X) = π(f(T )) it follows that<br />

f(σ e (T )) = f(σ(π(T ))) = σ(f(π(T ))) = σ(π(f(T ))) = σ e (f(T )).<br />

Theorem 1.11.2. If T ∈ B(X) and f is analytic in a neighborhood of σ(T ), then<br />

f(σ b (T )) = σ b (f(T ))<br />

Proof. Since by the analyticity of f, f(acc K) = acc f(K), it follows that<br />

f(σ b (T )) = f(σ e (T ) ∪ acc σ(T ))<br />

= f(σ e (T )) ∪ f(acc σ(T ))<br />

= σ e (f(T )) ∪ acc σ(f(T ))<br />

= σ b (f(T )).<br />

Theorem 1.11.3. If T ∈ B(X) and p is a polynomial then<br />

ω(p(T )) ⊆ p(ω(T )).<br />

Proof. Let p(z) = a 0 + a 1 z + · · · + a n z n ; thus p(z) = c 0 (z − α 1 ) · · · (z − α n ). Then<br />

p(T ) = c 0 (T − α 1 I) · · · (T − α n I).<br />

We now claim that<br />

0 /∈ p(ω(T )) =⇒ c 0 (z − α 1 ) · · · (z − α n ) ≠ 0 for each λ ∈ ω(T )<br />

=⇒ λ ≠ α i for each λ ∈ ω(T )<br />

=⇒ T − α i I is Weyl for each i = 1, 2, . . . n<br />

=⇒ c 0 (T − α 1 I) · · · (T − α n I) is Weyl<br />

=⇒ 0 /∈ ω(p(T ))<br />

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