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Woo Young Lee Lecture Notes on Operator Theory

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CHAPTER 2.<br />

WEYL THEORY<br />

Proof. Newburgh’s theorem is stated as follows: if in a Banach algebra A, {a i } i is a<br />

sequence of elements commuting with a ∈ A and such that a i → a, then lim σ(a i ) =<br />

σ(a). If π denotes the can<strong>on</strong>ical homomorphism of B(X) <strong>on</strong>to the Calkin algebra<br />

B(X)/K(X), then the assumpti<strong>on</strong>s give that π(T n ) → π(T ) and [π(T n ), π(T )] = 0<br />

for each n. Hence, lim σ(π(T n )) = σ(π(T )); that is, lim σ e (T n ) = σ e (T ).<br />

Theorem 2.3.3. Suppose that T, T n ∈ B(X), for n ∈ Z + , are such that T n c<strong>on</strong>verges<br />

to T . If [T n , T ] ∈ K(X) for each n, then<br />

lim ω(f(T n )) = ω(f(T )) for every f ∈ H(σ(T )). (2.24)<br />

Remark. Because T n → T , by the upper-semic<strong>on</strong>tinuity of the spectrum, there is<br />

a positive integer N such that σ(T n ) ⊆ V whenever n > N. Thus, in the left-hand<br />

side of (2.24) it is to be understood that n > N.<br />

Proof. If T n and T commute modulo the compact operators then, whenever Tn<br />

−1 and<br />

T −1 exist, T n , T, Tn<br />

−1 and T −1 all commute modulo the compact operators. Therefore<br />

r(T n ) and r(T ) also commute modulo K(X) whenever r is a rati<strong>on</strong>al functi<strong>on</strong> with no<br />

poles in σ(T ) and n is sufficiently large. Using Runge’s theorem we can approximate<br />

f <strong>on</strong> compact subsets of V by rati<strong>on</strong>al functi<strong>on</strong>s r who poles lie off of V . So there<br />

exists a sequence of rati<strong>on</strong>al functi<strong>on</strong>s r i whose poles lie outside of V and r i → f<br />

uniformly <strong>on</strong> compact subsets of V . If n > N, then by the functi<strong>on</strong>al calculus,<br />

f(T n )f(T ) − f(T )f(T n ) = lim<br />

i<br />

(<br />

ri (T n )r i (T ) − r i (T )r i (T n ) ) ,<br />

which is compact for each n. Furthermore,<br />

∫<br />

1<br />

||f(T n ) − f(T )|| = || f(λ) ( (λ − T n ) −1 − (λ − T ) −1) dλ||<br />

2πi Γ<br />

≤ 1 l(Γ) max |f(λ)| · max<br />

2πi ||(λ − T n) −1 − (λ − T ) −1 || ,<br />

λ∈Γ λ∈Γ<br />

where Γ is the boundary of V and l(Γ) denotes the arc length of Γ. The righthand<br />

side of the above inequality c<strong>on</strong>verges to 0, and so f(T n ) → f(T ). By Lemma<br />

2.25, lim σ e (f(T n )) = σ e (f(T )). The arguments used by J.B. C<strong>on</strong>way and B.B.<br />

Morrel in Propositi<strong>on</strong> 3.11 of [CoM] can now be used here to obtain the c<strong>on</strong>clusi<strong>on</strong><br />

lim ω(f(T n )) = ω(f(T )).<br />

In general there is <strong>on</strong>ly inclusi<strong>on</strong> for the Weyl spectrum:<br />

Theorem 2.3.4. If T ∈ B(X) then<br />

ω(p(T )) ⊆ p(ω(T )) for every polynomial p.<br />

Proof. We can suppose p is n<strong>on</strong>c<strong>on</strong>stant. Suppose λ /∈ pω(T ). Writing p(µ) − λ =<br />

a(µ − µ 1 )(µ − µ 2 ) · · · (µ − µ n ), we have<br />

p(T ) − λI = a(T − µ 1 I) · · · (T − µ n I). (2.25)<br />

For each i, p(µ i ) = λ /∈ pω(T ), so that µ i /∈ ω(T ), i.e., T − µ i I is weyl. It thus follows<br />

from (2.25) that p(T ) − λI is Weyl since the product of Weyl operators is Weyl.<br />

54

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