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SKF - Rolling Bearings

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Selecting bearing size<br />

Calculation examples<br />

Example 1: Basic rating life and <strong>SKF</strong> rating life<br />

An <strong>SKF</strong> Explorer 6309 deep groove ball bearing<br />

is to operate at 3 000 r/min under a constant<br />

radial load F r = 10 kN. Oil lubrication is to be<br />

used, the oil has an actual kinematic viscosity<br />

n = 20 mm 2 /s at normal operating temperature.<br />

The desired reliability is 90% and it is<br />

assumed that the operating conditions are<br />

very clean. What are the basic and <strong>SKF</strong> rating<br />

lives?<br />

a) The basic rating life for 90% reliability is<br />

q C w 3<br />

L 10 = —<br />

< P z<br />

From the product table for bearing 6309, C =<br />

55,3 kN. Since the load is purely radial, P = F r =<br />

10 kN († Equivalent dynamic bearing load,<br />

page 85).<br />

q 55,3 w 3<br />

L 10 = –—–<br />

< 10 z<br />

= 169 million revolutions<br />

or in operating hours, using<br />

10 6<br />

L 10h = —–– L 10<br />

60 n<br />

1 000 000<br />

L 10h = ————– ¥ 169<br />

60 ¥ 3 000<br />

= 940 operating hours<br />

b) The <strong>SKF</strong> rating life for 90% reliability is<br />

L 10m = a 1 a <strong>SKF</strong> L 10<br />

• As a reliability of 90% is required, the L 10m<br />

life is to be calculated and a 1 = 1 († table 1,<br />

page 65).<br />

• From the product table for bearing 6309,<br />

d m = 0,5 (d + D) = 0,5 (45 + 100) = 72,5 mm<br />

• From diagram 5 († page 72), the rated oil<br />

viscosity at operating temperature for<br />

a speed of 3 000 r/min, n 1 = 8,15 mm 2 /s.<br />

Therefore, k = n/n 1 = 20/8,15 = 2,45<br />

• From the product table P u = 1,34 kN and<br />

P u /P = 1,34/10 = 0,134. As the conditions<br />

are very clean, h c = 0,8 († table 4, page 74)<br />

and h c (P u /P) = 0,107. With k = 2,45 and<br />

using the <strong>SKF</strong> Explorer scale in diagram 1<br />

(† page 66), the value of a <strong>SKF</strong> = 8 is<br />

obtained. Then, according to the <strong>SKF</strong> rating<br />

life equation<br />

L 10m = 1 ¥ 8 ¥ 169<br />

= 1 352 million revolutions<br />

or in operating hours using<br />

10 6<br />

L 10mh = —–– L 10m<br />

60 n<br />

1 000 000<br />

L 10mh = ————– ¥ 1 352<br />

60 ¥ 3 000<br />

= 7 512 operating hours<br />

Example 2: Check contamination conditions<br />

An existing application has to be reviewed.<br />

An <strong>SKF</strong> Explorer 6309-2RS1 deep groove<br />

ball bearing with integral seals and standard<br />

grease fill is working under the same conditions<br />

as described in example 1 (k = 2,45). The<br />

con tam in ation conditions of this application<br />

have to be checked to determine if it is possible<br />

to use a more cost-effective bearing for a<br />

min imum requisite life of 3 000 hours of<br />

operation.<br />

• Considering grease lubrication and integral<br />

seals, the level of contamination can be<br />

characterized as high cleanliness and from<br />

table 4 († page 74), h c = 0,8.<br />

With P u /P = 0,134, h c (P u /P) = 0,107, using<br />

the <strong>SKF</strong> Explorer scale in diagram 1<br />

(† page 66) and k = 2,45, a <strong>SKF</strong> = 8.<br />

L 10mh = 8 ¥ 940 = 7 520 operating hours<br />

90

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