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We shall apply the above lemma to the complexes<br />
Ck = � M(ËΛ L1 , g1) ⊗ M(ËΛ L2 , g2) �<br />
k+n , C′ k = F Θ k (H1 ⊕ H2, J1 ⊕ J2),<br />
and to the chain maps K Λ 0 and K Λ α0 . The tensor products KΛ 0 ⊗K Λ α0 and KΛ α0 ⊗KΛ 0 are represented<br />
by the coupling - in two different orders - of the corresponding elliptic boundary value problems.<br />
4.7. Proposition. The chain maps K Λ 0 ⊗ KΛ α0 and KΛ α0 ⊗ KΛ 0<br />
are homotopic.<br />
Constructing a homotopy between the coupled problems is easier than dealing with the original<br />
ones: we can keep α0 fixed and rotate the boundary condition on the initial part of the half-strip.<br />
This argument is similar to an alternative way, due to Hofer, to prove the gluing statements in<br />
standard Floer homology. Details of the proof of Proposition 4.7 are contained in section 6.5<br />
below.<br />
Here we just construct the cycle ǫ and the chain map δ required in Lemma 4.6. Since changing<br />
the Lagrangians L1 and L2 (and the corresponding Hamiltonian) changes the chain maps appearing<br />
in diagram (53) by a chain homotopy, we are free to choose the Lagrangians so to make the<br />
construction easier.<br />
We consider a Lagrangian of the form<br />
where the potential V1 ∈ C ∞ (Ì×M) satisfies<br />
L1(t, q, v) := 1<br />
2 〈v, v〉 − V1(t, q),<br />
V1(t, q) < V1(t, q0) = 0, ∀t ∈Ì, ∀q ∈ M \ {q0}, (58)<br />
The corresponding Euler-Lagrange equation is<br />
HessV1(t, q0) < 0, ∀t ∈Ì. (59)<br />
∇tγ ′ (t) = −gradV1(t, γ(t)), (60)<br />
where ∇t denotes the covariant derivative along the curve γ. By (58) and (59), the constant curve<br />
q0 is a non-degenerate minimizer for the action functionalËΛ L1 on the free loop space (actually, it<br />
is the unique global minimizer), so<br />
m Λ (q0, L1) = 0.<br />
Notice also that the equilibrium point q0 is hyperbolic and unstable. We claim that there exists<br />
ω > 0 such that<br />
every solution γ of (60) such that γ(0) = γ(1), other than γ(t) ≡ q0, satisfiesËL1(γ) ≥ ω. (61)<br />
Assuming the contrary, there exists a sequence (γh) of solutions of (60) with γh(0) = γh(1) and<br />
0