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(c) There remains to study the case Rh · αh → c > 0. Again we rescale vh(s, t) = uh(αhs, αht),<br />

which now has to converge to a non-constant J-holomorphic map v on the upper half plane.<br />

After applying a suitable conformal coordinate change and transforming the non-local boundary<br />

conditions into local ones, we can view v as a map on the half strip v: Σ + → T ∗ M 4 ,<br />

satisfying the boundary conditions<br />

v(0, t) ∈ N ∗ ∆ Θ M for t ∈ [0, 1],<br />

v(s, 0) ∈ N ∗ (∆M × ∆M) for s ≥ 0,<br />

v(s, 1) ∈ N ∗ ∆ M 2 for s ≥ 0.<br />

Applying again the removal of singularities for s → ∞ we obtain v as a J-holomorphic triangle<br />

with boundary on three conormals. Hence, v would have to be constant, contradicting<br />

again the rescaling procedure.<br />

This shows the uniform convergence of a subsequence of (uh).<br />

Localization. It is convenient to transform the nonlocal boundary conditions (164) and (166)<br />

into local boundary conditions, by the usual method of doubling the space: given u : Σ → T ∗ M 2<br />

we define ũ : Σ → T ∗ M 4 as<br />

ũ(s, t) := � u(s/2, t/2), −u(s/2, 1 − t/2 � .<br />

Then u solves (163) if and only if ũ solves the equation<br />

with upper boundary condition<br />

where the Hamiltonian ˜ K : [0, 1] × T ∗ M 4 →Êis defined by<br />

∂ J, ˜ K (ũ) = 0, (167)<br />

ũ(s, 1) ∈ N ∗ ∆ M 2 ∀s ∈Ê, (168)<br />

˜K(t, x1, x2, x3, x4) := 1<br />

2 K(t/2, x1, x2) + 1<br />

2 K(1 − t/2, −x3, −x4).<br />

Moreover, u satisfies (164) if and only if ũ satisfies<br />

⎧<br />

⎨ N<br />

ũ(s, 0) ∈<br />

⎩<br />

∗∆M2 if s ≤ 0,<br />

N ∗∆Θ M if 0 ≤ s ≤ 2α,<br />

N ∗ (∆M × ∆M) if s ≥ 2α,<br />

whereas u satisfies (166) if and only if ũ satisfies<br />

ũ(s, 0) ∈<br />

� N ∗ ∆M 2 if s ≤ 0,<br />

N ∗ (∆M × ∆M), if s ≥ 0.<br />

Finally, the asymptotic condition (165) is translated into<br />

lim<br />

s→−∞ ũ(s, t) = � −x1(−t/2), x2(t/2), x1(t/2 − 1), −x2(1 − t/2) � ,<br />

lim<br />

s→+∞ ũ(s, t) = � −z(1/2 − t/4), z(1/2 + t/4), z(t/4), −z(1 − t/4) � .<br />

(169)<br />

(170)<br />

(171)<br />

Let u0 ∈ M Λ Υ (x1, x2; z). We must prove that there exists a unique connected component of<br />

M Υ GE (x1, x2; z) containing a curve α ↦→ (α, uα) which converges to (0, u0), in the sense of Lemma<br />

6.6.<br />

Let ũ0 be the map from Σ to T ∗ M 4 associated to u0: ũ0 solves (167) with boundary conditions<br />

(168), (170), and asymptotic conditions (171). Since we are looking for solutions which converge<br />

95

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