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with non-local boundary conditions<br />

⎧<br />

⎨ N<br />

(u(s, 0), −u(s, 1)) ∈<br />

⎩<br />

∗∆M2 if s ≤ 0,<br />

N ∗∆Θ M if 0 ≤ s ≤ α,<br />

N ∗ (∆M × ∆M) if s ≥ α,<br />

and asymptotics<br />

(164)<br />

lim<br />

s→−∞ u(s, t) = � −x1(−t), x2(t) � , lim<br />

s→+∞ u(s, t) = � −z((1 − t)/2), z((1 + t)/2) � . (165)<br />

Similarly, we can view the space M Λ Υ (x1, x2; z) as the space of maps u : Σ → T ∗M 2 solving the<br />

equation (163) with asymptotics (165) and non-local boundary conditions<br />

(u(s, 0), −u(s, 1)) ∈<br />

� N ∗ ∆M 2 if s ≤ 0,<br />

N ∗ (∆M × ∆M) if s ≥ 0.<br />

(166)<br />

Compactness. We start with the following compactness results, which also clarifies the sense<br />

of the convergence in (ii):<br />

6.6. Lemma. Let (αh, uh) be a sequence in M Υ GE (x1, x2; z) with αh → 0. Then there exists<br />

u0 ∈ M Λ Υ (x1, x2; z) such that up to a subsequence uh converges to u0 in C∞ loc (Σ \ {0, i}), in<br />

C∞ (Σ ∩ {|Re z| > 1}), and uniformly on Σ.<br />

Proof. Since the sequence of maps (uh) has uniformly bounded energy, Proposition 6.2 implies a<br />

uniform L ∞ bound. Then, the usual non-bubbling-off analysis for interior points and boundary<br />

points away from the jumps in the boundary condition implies that, modulo subsequence, we have<br />

uh → u0 in C ∞ loc (Σ \ {0, i}, T ∗ M 2 ),<br />

where u0 is a smooth solution of equation (163) on Σ \ {0, i} with bounded energy and satisfying<br />

the boundary condions (166), except possibly at 0 and i. By Proposition 6.5, the singularities<br />

0 and i are removable, and u0 satisfies the boundary condition also at 0 and i. By the index<br />

formula (162) and transversality, the sequence uh cannot split, so u0 satisfies also the asymptotic<br />

conditions (165), and uh → u0 in C ∞ (Σ ∩ {|Rez| > 1}). Therefore, u0 belongs to M Λ Υ (x1, x2; z),<br />

and there remain to prove that uh → u uniformly on Σ.<br />

We assume by contraposition that (uh) does not converge uniformly on Σ. By Ascoli-Arzelà<br />

theorem, there must be some blow-up of the gradient. That is, modulo subsequence, we can find<br />

zh ∈ Σ converging either to 0 or to i such that<br />

Rh := |∇uh(zh)| = �∇uh�∞ → ∞.<br />

For sake of simplicity, we only consider the case where zh = (sh, 0) → 0, 0 < sh < αh → 0. The<br />

general case follows along analogous arguments using additional standard bubbling-off arguments.<br />

For more details, see e.g. [HZ94, section 6.4].<br />

We now have to make a case distinction concerning the behaviour of the quantity 0 < Rh ·αh <<br />

∞:<br />

(a) The case of a diverging subsequence Rhj · αhj → ∞ can be handled by conformal rescaling<br />

vj(s, t) := uhj(shj +s/Rhj, t/Rhj) which provides us with a finite energy disk with boundary<br />

on a single Lagrangian submanifold of conormal type. This has to be constant due to the<br />

vanishing of the Liouville 1-form on conormals, contradicting the convergence of |∇vj(0)| = 1.<br />

(b) The case of convergence of a subsequence Rhj · αhj → 0 can be dealt with by rescaling<br />

vj(s, t) := uhj(shj + αhj, αhjt). Now vk has to converge uniformly on compact subsets<br />

towards a constant map, since �∇vj�∞ = |∇vj(0)| = Rhj · αhj → 0. This in particular<br />

implies that uhj(·, 0) |[0,αh j ] converges uniformly to a point contradicting the contraposition<br />

assumption.<br />

94

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