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Log----------­<br />

CO-Cl<br />

LogW U B = 9. 36Log (SN+ 1) - 1. 075 +<br />

+ LogR-' + 0.372(Si-3.0l<br />

4286<br />

0.40 + ----------­<br />

(SN+l)""'"<br />

Compte tenues des hypothéses précédentes et en posant C, = 0.75 pour<br />

les mêmes<br />

raisons que lors du choix du PSI terminal,la formule devient:<br />

4.2-1.75<br />

Log<br />

4.2-1).75<br />

LOgW t 2 B = 9:36Log(SN+l) - 1.075 + ---------------- + LogR-' + 0.372(Si-3.0l<br />

4286<br />

0.40 + ------------<br />

(SN<br />

+ 1)"','"<br />

+ Log (O. 5)-'<br />

D'où la formule 1<br />

0.15(SN+l)"'·'"<br />

LOgW t 2 B = 9.36Log(SN+li - 0.774 -<br />

~ 0.372

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