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Boundary Lyer Theory

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292 XIT. Tl~er~nnl Imn~dary layers in laminar flow g. Thermal boundary layers in forced flow 293<br />

evcn in the case of moderately-valued Prandtl numbers. At the stagnation point,<br />

the corresponding cquation is<br />

N, = 0.661 P1I3 1/% (stagnation point, P -+ oo) . (12.6213)<br />

Analogous, simple asymptotic formulae can also be established for the case of frcc<br />

convect,ion on n verlical flat plate, [73], see also eqns. (12.118a) and (12.1181)).<br />

g. Thermnl bounilnry layers in forced Row<br />

In the present section we shall consider several examples of thermal boundary<br />

layors in forced flow. In solving thcso problems, uso will bo made of tho simplified<br />

thermal boundary-layer equations. Just as in the case of a velocity boundary layer,<br />

the general problem of evaluating tho thermal boundary layer for a body of arbitrary<br />

shape proves to be extremely difficult, so that we shall begin with the simpler<br />

example of the flat plate at zero incidence.<br />

1. Parallel Row paet a Bat platc at zero incidence. We shall assume that the<br />

x-axis is placed in the plane of the plate in the direction of flow, the y-axis being<br />

at right ar~glcs to it and to the flow, with the origin at the leading cdgc. The boundarylayer<br />

equations for incompressible flow and constant properties (i. e. independent<br />

of temperature) have been given in eqns. (12.61 a, b, c): assuming that the buoyancy<br />

forces are equal to zero as well as that dpldz = 0 [18, 941, we obtain<br />

'I'hc: 1)ountlary ronclitions arc:<br />

11 = 0 : u = v = 0 ; T == T,,, or aT/8g =O<br />

'I'he vrlocit8y ficld is it~tlcpcndrnt, of t,hc tcmprraturc firltl so that tlrc two Ilow<br />

equations (12.03a, b) can be solved first and the result can be employed to evaluatc<br />

the tscmpcmtnrc field. An important rclatior~ship between the velocity distribution<br />

and thc temperature distribution can bc obtained immediately from eqns. (12.63 b)<br />

:md (I 2.fR c). Jf lhc hcat of friction p may be neglected in eqn. (12.63~).<br />

the two rquat.ions, (12.03b) and (12.63c), become identical if T is rrplaced by 76 in<br />

the sccond cqr~at~ion a.id if, in addition, the properties of the fluid satisfy the equation<br />

If the frictional heat is neglected then a temperature field exists only if there is a<br />

difference in temperature between thc wall and the extcrnal flow, e.g., if Tw - T, > 0<br />

(cooling). Hence it follows that for a flat plate at zero incidence in psrallcl Row<br />

and at small velocities the temperature arid velocity distributions arc idcr~tical<br />

provided that the Prandtl number is equal to unity:<br />

Thi~ result corresponds to eqn. (12.52) which Icd us lo thc f~rrnulat~ion of Llw<br />

important Iteynolds analogy between heat transfer and skin friction.<br />

11. Blasius introduced new variables for thc solution of the flow rquat.ions,<br />

sce oqns. (7.24) and (7.26). (y) is 1110 slrcnm fnnclion):<br />

'rhe diffcrcntial cquation for /(q), cqn. (7.28) bccornos<br />

f f" + 21"' =0,<br />

with thc boundary conditions: rl = 0 : f = f' = 0 ; 11 =- cm : 1' L- I . 'I'l~e solution<br />

of these equations was given in Chap. VII, Table 7.1.<br />

Including the eflect of frictional hcat, as seon from eqn. (12.63c), the temperature<br />

distribution T(7) is given by the equation<br />

It is convenient to represent thc general solution of eqn. (12.65) by tho super-<br />

position of two solutions of the form:<br />

ITcrc O1(7) dcnotes the grncml solution of thc hornogcncous cqu:~tion and 02(t7)<br />

denotes a particular solution of the non-homogeneous equation. It is, further,<br />

convenient to choose the boundary conditions for 01(7) and O,(q) so as to rnakc<br />

01(7) the solution of the cooling problem with a prescribed temperature diKcrcnce<br />

betwecn the wall and thc external stream, T, - T, with 02(7) giving the solution<br />

for the adiabatic wall. Thus 01(7) and Oz(v) satisfy the following equations:<br />

with 0, -1 1 nt 7 -1 0 arid O1 -- 0 nt 11 == oc> , r ~ l

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