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Study Guide and Intervention (continued) - MathnMind

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12-9<br />

NAME ______________________________________________ DATE ____________ PERIOD _____<br />

<strong>Study</strong> <strong>Guide</strong> <strong>and</strong> <strong>Intervention</strong> (<strong>continued</strong>)<br />

Solving Rational Equations<br />

Extraneous Solutions When you use cross multiplication or use the LCD of two<br />

rational expressions, you may get values for the variable that are not solutions of the<br />

original equation. Such values are called extraneous solutions.<br />

Example<br />

Solve .<br />

30(x 1) 5(x2 15 5<br />

<br />

x2 1 2(x 1)<br />

15<br />

<br />

x2 1<br />

1) Cross multiply.<br />

5<br />

Original equation<br />

2(x 1)<br />

30x 30 5x 2 5 Distributive Property<br />

0 5x 2 30x 30 5 Add 30x 30 to each side.<br />

0 5x 2 30x 25 Simplify.<br />

0 5(x 2 6x 5) Factor.<br />

0 5(x 1)(x 5) Factor.<br />

x 1 or x 5 Zero Product Property<br />

The number 1 is an extraneous solution, since 1 is an excluded value for x. So, 5 is the<br />

solution of the equation.<br />

Exercises<br />

Solve each equation. State any extraneous solutions.<br />

6x 2x 8<br />

4x 1<br />

1. 4 2. <br />

x 1 x 1<br />

x 2 x 2<br />

5 x 1<br />

x 4<br />

3. 4. x<br />

x 2 3<br />

x 3 3 x<br />

x 4<br />

x 1<br />

5. x 6. <br />

x 2 2 x<br />

x2 25 x 5<br />

x 1<br />

4z<br />

6 4<br />

7. 0 8. x2 36 x 6<br />

z2 4z 3 z 3 z 1<br />

p 2<br />

9. 4 10. x2 x<br />

16<br />

2 4<br />

16<br />

<br />

4 p p 4<br />

x 4<br />

© Glencoe/McGraw-Hill 754 Glencoe Algebra 1

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