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The construction of the wonderful canon of logarithms

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40 Construction <strong>of</strong> <strong>the</strong> Canon.<br />

find <strong>the</strong> logarithm <strong>of</strong> this sine now contained in<br />

<strong>the</strong> table, and <strong>the</strong>n add to it <strong>the</strong> logarithmic difference<br />

which <strong>the</strong> short table indicates as required<br />

by <strong>the</strong> preceding multiplication.<br />

Example.<br />

IT is<br />

378064. Since this sine is outside <strong>the</strong> limits<br />

required to find <strong>the</strong> logarithm <strong>of</strong> <strong>the</strong> sine<br />

<strong>of</strong> <strong>the</strong> Radical table, let it be multiplied by some<br />

proportional number in <strong>the</strong> foregoing short table,<br />

as by 20, when it will become 7561280. As this<br />

now falls within <strong>the</strong> Radical table, seek for its<br />

logarithm (by 50) and you will obtain 2795444.9,<br />

to which add 29957311.56, <strong>the</strong> difference in <strong>the</strong><br />

short table corresponding to <strong>the</strong> proportion <strong>of</strong><br />

Where-<br />

twenty to one, and you have 32752756.4.<br />

fore 32752756 is <strong>the</strong> required logarithm <strong>of</strong> <strong>the</strong><br />

given sine 378064.<br />

55. As half radius is to <strong>the</strong> sine <strong>of</strong> half a given arc, so is<br />

<strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong> <strong>the</strong> half arc to <strong>the</strong> sine <strong>of</strong><strong>the</strong><br />

whole arc.<br />

Let a b be radius, and a b c its double, on<br />

which as diameter is described a semicircle. On<br />

this lay <strong>of</strong>f <strong>the</strong> given arc a e, bisect it in d, and<br />

from e in <strong>the</strong> direction<br />

<strong>of</strong> c lay <strong>of</strong>f e h,<br />

<strong>the</strong> complement <strong>of</strong><br />

d e, half <strong>the</strong> given<br />

arc. <strong>The</strong>n h c is<br />

necessarily equal to<br />

e h, since <strong>the</strong> quadrant<br />

d e h must equal<br />

i<br />

<strong>the</strong> remaining quadrant made up <strong>of</strong> <strong>the</strong> arcs a d<br />

and h c. Draw e i perpendicular to a i c, <strong>the</strong>n e i<br />

is

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