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The construction of the wonderful canon of logarithms

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Remarks on Appendix.<br />

6i<br />

<strong>the</strong> quoiients and <strong>the</strong> Logarithms <strong>of</strong> <strong>the</strong> divisors will be<br />

reciprocally proportional.<br />

O<strong>the</strong>rwise <strong>the</strong> ratio will not be exactly <strong>the</strong> same on both<br />

sides ; never<strong>the</strong>less, if <strong>the</strong> divisors be very small, and <strong>the</strong><br />

dividends sufficiently large, so that <strong>the</strong> quotients are very<br />

m.any, <strong>the</strong> defect from- proportionality will scarcely, or not<br />

even scarcely, be perceived.<br />

Hence it follows that <strong>the</strong> logarithm )<br />

[C]<br />

Let two numbers be taken, lo and 2, or any o<strong>the</strong>rs you<br />

please. Let <strong>the</strong> Logarithm <strong>of</strong> <strong>the</strong> first, namely 100, be<br />

given ; it is required to find <strong>the</strong> Logarithm <strong>of</strong> <strong>the</strong> second.<br />

In <strong>the</strong> first place, let <strong>the</strong> second, 2. multiply itself continuously<br />

until <strong>the</strong> number <strong>of</strong><strong>the</strong> products is exceeded, by unity<br />

<strong>The</strong>n let <strong>the</strong> last<br />

only, by <strong>the</strong> given Logarithm <strong>of</strong> <strong>the</strong> first.<br />

product be divided as <strong>of</strong>ten as possible by <strong>the</strong>first number,<br />

10. and again in like m-anner by <strong>the</strong> second number, 2.<br />

<strong>The</strong> number <strong>of</strong>quotients in <strong>the</strong> latter case will be 100, ^for<br />

<strong>the</strong> product is its hundredthpower ; and if a number be multiplied<br />

by itself a given number <strong>of</strong> times forming a certain<br />

product, <strong>the</strong>n it will divide <strong>the</strong> product as m,any times and<br />

once more ; for exam,ple, if 2)<br />

be multiplied by itself four<br />

times it makes 243, and <strong>the</strong> same 3 divides 243 five times,<br />

<strong>the</strong> quotients being Bi, 27, 9, 3, i.) In <strong>the</strong> former case,<br />

where <strong>the</strong> product is continually divided by 10, it is manifest<br />

that <strong>the</strong> number <strong>of</strong> quotients falls short <strong>of</strong> <strong>the</strong> number<br />

<strong>of</strong> places in <strong>the</strong> dividend by one only. <strong>The</strong>refore (by <strong>the</strong><br />

preceding proposition) since <strong>the</strong> same product is divided by<br />

two given numbers as <strong>of</strong>ten aspossible, <strong>the</strong> numbers <strong>of</strong> <strong>the</strong><br />

quotients and <strong>the</strong> Logarithms <strong>of</strong> <strong>the</strong> divisors will be reciprocally<br />

proportional. But, <strong>the</strong> number <strong>of</strong> quotients by <strong>the</strong><br />

second being equal to <strong>the</strong> Logarithm <strong>of</strong> <strong>the</strong> first, <strong>the</strong> num-<br />

H 3 ber

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