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The construction of the wonderful canon of logarithms

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;<br />

Trigonometrical Propositions. 67<br />

CAD will be produced, giving us C A D.<br />

10. Given A D, cS^ <strong>the</strong> angle D with <strong>the</strong> side A B, to find<br />

<strong>the</strong> angle A.<br />

Multiply radius by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

A D, divide <strong>the</strong> product by <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> complement<br />

<strong>of</strong> D, and <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

Again,<br />

multiply <strong>the</strong> tangent <strong>of</strong> A D by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement<br />

<strong>of</strong> C A D, divide <strong>the</strong> product by <strong>the</strong> tangent<br />

<strong>of</strong> A B, and <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

B A C will be produced, giving B A C. <strong>The</strong>n <strong>the</strong><br />

sum or difference <strong>of</strong> <strong>the</strong> arcs B A C and CAD<br />

will be <strong>the</strong> required angle BAD.<br />

1 1. Given KY), & <strong>the</strong> angle D with <strong>the</strong> angle A, to find <strong>the</strong><br />

side A B.<br />

Multiply radius by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

A D, divide <strong>the</strong> product by <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> complement<br />

<strong>of</strong> D, and you have <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> complement<br />

<strong>of</strong> C A D CAD ; being thus known, <strong>the</strong><br />

difference or sum <strong>of</strong> <strong>the</strong> same and <strong>the</strong> whole angle<br />

A is <strong>the</strong> angle B A C. Multiply <strong>the</strong> tangent <strong>of</strong><br />

A D by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong> C A D<br />

divide <strong>the</strong> product by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

B A C, and you will have <strong>the</strong> tangent <strong>of</strong> A B.<br />

1 2. Given A D, dr" <strong>the</strong> angle D with <strong>the</strong> angle A, to find <strong>the</strong><br />

third angle B.<br />

Multiply radius by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

A D, divide <strong>the</strong> product by <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> complement<br />

<strong>of</strong> D, and <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong> B<br />

will be produced, from which we have <strong>the</strong> angle<br />

required.<br />

Given A D, & <strong>the</strong> angle D with <strong>the</strong> angle A,<br />

to find <strong>the</strong> side B D.<br />

This follows from <strong>the</strong> above, but in this form <strong>the</strong><br />

problem would require <strong>the</strong> " Rule <strong>of</strong> Three" to be<br />

I 2 three

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