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The construction of the wonderful canon of logarithms

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Trigonometrical Propositions. 65<br />

4. Given <strong>the</strong> side h. T>, & <strong>the</strong> angles T> & V>, to find <strong>the</strong><br />

side B D.<br />

D ;<br />

Multiply radius by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

divide by <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

A D, and you will obtain <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> arc<br />

C D :<br />

<strong>the</strong>n multiply <strong>the</strong> sine <strong>of</strong> C D by <strong>the</strong> tangent<br />

<strong>of</strong> D ; divide <strong>the</strong> product by <strong>the</strong> tangent <strong>of</strong> B, and<br />

<strong>the</strong> sine <strong>of</strong> B C will result :<br />

C D, and you have B D.<br />

add or subtract B C and<br />

5. Given <strong>the</strong> side A D, df <strong>the</strong> angles D cSf B, /c find <strong>the</strong><br />

angle A.<br />

Multiply radius by <strong>the</strong> sine<br />

<strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

divide by <strong>the</strong> tangent <strong>of</strong>' <strong>the</strong> complement <strong>of</strong><br />

A D ;<br />

D, and <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> complement <strong>of</strong> C A D<br />

will be produced ; whence we have CAD itself.<br />

Similarly multiply <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong> B<br />

by <strong>the</strong> sine <strong>of</strong> C A D ;<br />

divide by <strong>the</strong> sine <strong>of</strong> <strong>the</strong><br />

complement <strong>of</strong> D, and <strong>the</strong> sine <strong>of</strong> B A C will be<br />

produced ;<br />

which being added to or subtracted from<br />

CAD, you will obtain <strong>the</strong> required angle BAD.<br />

6. Given KTi, & <strong>the</strong> angle D with <strong>the</strong> side B D, to find<br />

<strong>the</strong> angle B.<br />

Multiply radius by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

divide by <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

D ;<br />

A D, and <strong>the</strong> tangent <strong>of</strong> C D will be produced ;<br />

arc C D subtract from, or add to, <strong>the</strong> side B D, and<br />

you have B C : <strong>the</strong>n multiply <strong>the</strong> sine <strong>of</strong> C D by<br />

<strong>the</strong> tangent <strong>of</strong> D ; divide <strong>the</strong> product by <strong>the</strong> sine <strong>of</strong><br />

B C, and you have <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> angle B.<br />

7. Given A D, cSj' <strong>the</strong> angle D with <strong>the</strong> side B D, to find<br />

<strong>the</strong> side A B.<br />

Multiply radius by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> complement <strong>of</strong><br />

D ;<br />

divide <strong>the</strong> product by <strong>the</strong> tangent <strong>of</strong> <strong>the</strong> com-<br />

be<br />

I<br />

produced<br />

plement <strong>of</strong> A D, and <strong>the</strong> tangent <strong>of</strong> C D will<br />

its

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