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The construction of the wonderful canon of logarithms

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74 Trigonometrical Propositions.<br />

Again, add toge<strong>the</strong>r <strong>the</strong> logarithm <strong>of</strong> <strong>the</strong> half difference,<br />

<strong>the</strong> logarithm <strong>of</strong> <strong>the</strong> complement <strong>of</strong> <strong>the</strong> half<br />

sum, and <strong>the</strong> logarithm <strong>of</strong> <strong>the</strong> tangent <strong>of</strong> half <strong>the</strong> base;<br />

subtract <strong>the</strong> logarithm <strong>of</strong> <strong>the</strong> sum and <strong>the</strong> logarithm<br />

<strong>of</strong> half radius, and you will have <strong>the</strong> second found.<br />

Proceed as above with <strong>the</strong> first and second found,<br />

and you will obtain <strong>the</strong> sides.<br />

[d]<br />

Ano<strong>the</strong>r way <strong>of</strong> <strong>the</strong> same.<br />

Multiply <strong>the</strong> secant <strong>of</strong> <strong>the</strong> complement <strong>of</strong> <strong>the</strong><br />

sum <strong>of</strong> <strong>the</strong> angles at <strong>the</strong> base by <strong>the</strong> tangent<br />

<strong>of</strong> half <strong>the</strong> base.<br />

Multiply <strong>the</strong> product by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> greater<br />

angle at <strong>the</strong> base, and you will have <strong>the</strong> first found.<br />

Multiply <strong>the</strong> same product by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> less<br />

angle, and you will have <strong>the</strong> second found,<br />

<strong>The</strong>n divide <strong>the</strong> sum <strong>of</strong> <strong>the</strong> first and second found<br />

by <strong>the</strong> square <strong>of</strong> radius, and you wiU have <strong>the</strong> tangent<br />

<strong>of</strong> half <strong>the</strong> sum <strong>of</strong> <strong>the</strong> sides.<br />

Also subtract <strong>the</strong> less from <strong>the</strong> greater and you will<br />

have <strong>the</strong> tangent <strong>of</strong> half <strong>the</strong> difference <strong>of</strong> <strong>the</strong> sides.<br />

Whence add <strong>the</strong> arcs corresponding to <strong>the</strong>se two<br />

tangents, and <strong>the</strong> greater side will be obtained ; subtract<br />

<strong>the</strong> less arc from <strong>the</strong> greater and you have <strong>the</strong><br />

less side.<br />

Of <strong>the</strong> five consecutive parts <strong>of</strong> a spherical triangle, s^ven<br />

<strong>the</strong> three intermediate, to find both extremes by one oper^<br />

ation and without <strong>the</strong> need <strong>of</strong>discriminating between <strong>the</strong><br />

several cases.<br />

(*) '^^ angles at <strong>the</strong> base, <strong>the</strong> sine <strong>of</strong> <strong>the</strong> half<br />

f^^<br />

^-^ difference is to <strong>the</strong> sine <strong>of</strong> <strong>the</strong> half sum, as <strong>the</strong><br />

sine <strong>of</strong> <strong>the</strong> difference is to a fourth which is <strong>the</strong> sum<br />

<strong>of</strong> <strong>the</strong> sines.<br />

And

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