The construction of the wonderful canon of logarithms
The construction of the wonderful canon of logarithms
The construction of the wonderful canon of logarithms
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68 Trigonometrical Propositions.<br />
<strong>The</strong>refore substitute A for D<br />
three times applied.<br />
and D for A, and <strong>the</strong> problem will be as follows :<br />
Given K D & <strong>the</strong> angle A with <strong>the</strong> angle D, to<br />
find <strong>the</strong> side B A.<br />
This is <strong>the</strong> same throughout as problem 1 1, and is<br />
solved by applying <strong>the</strong> " Rule <strong>of</strong> Three " twice only.<br />
<strong>The</strong> use and importance <strong>of</strong> half-versed<br />
sines.<br />
1. r~^ IvEN two sides & <strong>the</strong> contained angle, to find <strong>the</strong><br />
VJJ" third side.<br />
From <strong>the</strong> half-versed sine <strong>of</strong> <strong>the</strong> sum <strong>of</strong> <strong>the</strong> sides<br />
subtract <strong>the</strong> half - versed sine <strong>of</strong> <strong>the</strong>ir difference<br />
multiply <strong>the</strong> remainder by <strong>the</strong> half-versed sine <strong>of</strong><br />
<strong>the</strong> contained angle ; divide <strong>the</strong> product by radius<br />
to this add <strong>the</strong> half-versed sine <strong>of</strong> <strong>the</strong> difference <strong>of</strong><br />
<strong>the</strong> sides, and you have <strong>the</strong> half-versed sine <strong>of</strong> <strong>the</strong><br />
required base.<br />
Given <strong>the</strong> base and <strong>the</strong> adjacent angles, <strong>the</strong> vertical<br />
angle will be found by similar reasoning.<br />
2. Conversely, given <strong>the</strong> three sides, to find any angle.<br />
From <strong>the</strong> half-versed sine <strong>of</strong> <strong>the</strong> base subtract <strong>the</strong><br />
half-versed sine <strong>of</strong> <strong>the</strong> difference <strong>of</strong> <strong>the</strong> sides multiplied<br />
by radius ; divide <strong>the</strong> remainder by <strong>the</strong> halfversed<br />
sine <strong>of</strong> <strong>the</strong> sum <strong>of</strong> <strong>the</strong> sides diminished by<br />
<strong>the</strong> half-versed sine <strong>of</strong> <strong>the</strong>ir difference, and <strong>the</strong> halfversed<br />
sine <strong>of</strong> <strong>the</strong> vertical angle will be produced.<br />
Given <strong>the</strong> three angles, <strong>the</strong> sides will be found by<br />
similar reasoning.<br />
3. Given two arcs, to find a third, whose sine shall be equal to<br />
<strong>the</strong> difference <strong>of</strong> <strong>the</strong> sines <strong>of</strong> <strong>the</strong> given arcs.<br />
Let