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The construction of the wonderful canon of logarithms

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72 Trigonometrical Propositions.<br />

14449; <strong>the</strong>ir half difference is 8° 59', and its logarithm<br />

1856956. Add <strong>the</strong>se <strong>logarithms</strong> and you have<br />

1 87 1 405; subtract 693 1 47 and <strong>the</strong>re remains 11 78258.<br />

<strong>The</strong> arc corresponding to this logarithm is 17° 56',<br />

which arc we call <strong>the</strong> third found.<br />

From <strong>the</strong> logarithm <strong>of</strong> <strong>the</strong> third found, subtract<br />

<strong>the</strong> <strong>logarithms</strong> <strong>of</strong> <strong>the</strong> given sides, namely 581260<br />

and 312858, and <strong>the</strong>re remains 283533; halve this<br />

and you have 141 766 for <strong>the</strong> logarithm <strong>of</strong> <strong>the</strong> half<br />

vertical angle 60° 12' 24-^'''. <strong>The</strong> whole vertical<br />

angle sought is <strong>the</strong>refore 120° 24' 49".<br />

Ano<strong>the</strong>r rule forfinding <strong>the</strong> base by prosthaphceresis.—<br />

N'<br />

\Given <strong>the</strong> sides and vertical angle, to find <strong>the</strong> base.\<br />

Ote <strong>the</strong> half difference between <strong>the</strong> versed sines<br />

<strong>of</strong> <strong>the</strong> sum and difference <strong>of</strong> <strong>the</strong> sides, and also<br />

<strong>the</strong> half-versed sine <strong>of</strong> <strong>the</strong> vertical angle. Look<br />

among <strong>the</strong> common sines for <strong>the</strong> values noted, and<br />

find <strong>the</strong> arcs corresponding to <strong>the</strong>m in <strong>the</strong> table.<br />

<strong>The</strong>n write for <strong>the</strong> second found <strong>the</strong> half difference<br />

<strong>of</strong> <strong>the</strong> versed sines <strong>of</strong> <strong>the</strong> sum and difference <strong>of</strong> <strong>the</strong>se<br />

arcs.<br />

Also, as before, take for <strong>the</strong> first found <strong>the</strong> halfversed<br />

sine <strong>of</strong> <strong>the</strong> difference <strong>of</strong> <strong>the</strong> sides.<br />

Add <strong>the</strong> first and second found, and you will<br />

obtain <strong>the</strong> half-versed sine <strong>of</strong> <strong>the</strong> base sought for.<br />

Conversely— \given <strong>the</strong> sides and <strong>the</strong> base, to find <strong>the</strong> vertical angle.']<br />

<strong>The</strong> first found will<br />

be, as before, <strong>the</strong> half-versed<br />

sine <strong>of</strong> <strong>the</strong> difference <strong>of</strong> <strong>the</strong> sides.<br />

From <strong>the</strong> half-versed sine <strong>of</strong> <strong>the</strong> base subtract <strong>the</strong><br />

first found and you will have <strong>the</strong> second found.<br />

Multiply <strong>the</strong> latter by <strong>the</strong> square <strong>of</strong> radius ; divide<br />

by

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