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Application Note AN-1150 - International Rectifier

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900mV<br />

V BOP<br />

750mV<br />

∆V BOP<br />

V BOP,AVG<br />

SEL>><br />

600mV<br />

80V<br />

V(R2:2)<br />

V IN<br />

40V<br />

0V<br />

1/2f AC<br />

Fig 6: Voltage waveform on the BOP pin is comprises a DC level (V BOP,AVG ) and a<br />

ripple voltage (∆V BOP )<br />

The DC level V BOP,AVG is given by:<br />

where<br />

V<br />

BOP,<br />

AVG<br />

=<br />

R<br />

BOP3<br />

R<br />

TOT<br />

⋅V<br />

ACAVG<br />

Hence:<br />

R TOT = R BOP1 +R BOP2 +R BOP3<br />

2<br />

VAC, AVG<br />

= 2 ⋅VIN<br />

( RMS)<br />

π<br />

V<br />

R<br />

2<br />

BOP3<br />

BOP, AVG<br />

= ⋅ 2<br />

RTOT<br />

π<br />

⋅V<br />

IN ( RMS )<br />

Thus V BOP,AVG depends only on the resistor divider and the AC input voltage.<br />

The ripple ∆V BOP is given by the transfer function represented by the resistor<br />

divider and the capacitor:<br />

Thus:<br />

where:<br />

∆V<br />

T ( s)<br />

=<br />

V<br />

R<br />

=<br />

⋅<br />

BOP BOP3<br />

AC , PK<br />

R<br />

( R<br />

TOT<br />

BOP1<br />

+ RBOP<br />

2<br />

)<br />

1 + sC<br />

BOP<br />

⋅<br />

RTOT<br />

∆ V<br />

BOP<br />

=<br />

ω<br />

O<br />

=<br />

( R<br />

2 ⋅V<br />

IN ( RMS )<br />

R<br />

⋅<br />

R<br />

BOP3<br />

TOT<br />

ω = 2π<br />

⋅ (2 ⋅ f<br />

AC<br />

)<br />

R<br />

TOT<br />

BOP1 + RBOP<br />

2<br />

) ⋅<br />

R<br />

⋅<br />

BOP3<br />

1<br />

1<br />

ω<br />

1 + ( )<br />

ω<br />

⋅ C<br />

BOP<br />

O<br />

2<br />

R<br />

BOP3<br />

www.irf.com <strong>AN</strong>-<strong>1150</strong><br />

15

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