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103 Trigonometry Problems

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17. Prove that<br />

4. Solutions to Introductory <strong>Problems</strong> 93<br />

(<br />

1 + a ) ( 1 + b ) (<br />

≥ 1 + √ ) 2<br />

2ab<br />

sin x cos x<br />

for all real numbers a,b,x with a,b ≥ 0 and 0 1 + 2ab + 2√ 2ab.<br />

By the arithmetic–geometric means inequality, we obtain<br />

a<br />

sin x +<br />

b<br />

cos x ≥<br />

2 √ ab<br />

√<br />

sin x cos x<br />

.<br />

By the double-angle formulas,wehavesinx cos x =<br />

2 1 sin 2x ≤ 2 1 , and so<br />

2 √ ab<br />

√<br />

sin x cos x<br />

≥ 2 √ 2ab<br />

and<br />

ab<br />

sin x cos x ≥ 2ab.<br />

Combining the last three inequalities gives the the desired result.<br />

18. In triangle ABC, sin A + sin B + sin C ≤ 1. Prove that<br />

min{A + B,B + C, C + A} < 30 ◦ .<br />

Solution: Without loss of generality, we assume that A ≥ B ≥ C. We<br />

need to prove that B + Ca) imply that sin B+sin C>sin A,sosinA+sin B+sin C>2 sin A.<br />

It follows that sin A<<br />

2 1 A+B+C<br />

, and the inequality A ≥<br />

3<br />

= 60 ◦ gives that<br />

A>150 ◦ ; that is, B + C

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