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103 Trigonometry Problems

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206 <strong>103</strong> <strong>Trigonometry</strong> <strong>Problems</strong><br />

The inequality is a special case of the power mean inequality.<br />

Schur’s Inequality<br />

Let x,y,z be nonnegative real numbers. Then for any r>0,<br />

x r (x − y)(x − z) + y r (y − z)(y − x) + z r (z − x)(z − y) ≥ 0.<br />

Equality holds if and only if x = y = z or if two of x,y,z are equal and the third is<br />

equal to 0.<br />

The proof of the inequality is rather simple. Because the inequality is symmetric<br />

in the three variables, we may assume without loss of generality that x ≥ y ≥ z.<br />

Then the given inequality may be rewritten as<br />

(x − y) [ x r (x − z) − y r (y − z) ] + z r (x − z)(y − z) ≥ 0,<br />

and every term on the left-hand side is clearly nonnegative. The first term is positive<br />

if x>y, so equality requires x = y, as well as z r (x − z)(y − z) = 0, which gives<br />

either x = y = z or z = 0.<br />

Sector<br />

The region enclosed by a circle and two radii of the circle.<br />

Stewart’s Theorem<br />

In a triangle ABC with cevian AD, write a =|BC|, b =|CA|, c =|AB|, m =<br />

|BD|, n =|DC|, and d =|AD|. Then<br />

d 2 a + man = c 2 n + b 2 m.<br />

This formula can be used to express the lengths of the altitudes and angle bisectors<br />

of a triangle in terms of its side lengths.<br />

Trigonometric Identities<br />

sin 2 a + cos 2 a = 1,<br />

1 + cot 2 a = csc 2 a,<br />

tan 2 x + 1 = sec 2 x.

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