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103 Trigonometry Problems

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5. Solutions to Advanced <strong>Problems</strong> 155<br />

It follows that<br />

( sin 2 ) 2 ( )<br />

nx sin nx sin(n + 1)x 2 ( sin nx cos(n + 1)x<br />

sin 2 =<br />

+<br />

x<br />

sin x<br />

sin x<br />

On the other hand,<br />

= s 2 + c 2 .<br />

s 2 + c 2 = (sin 2x + sin 4x +···+sin 2nx) 2<br />

+ (cos 2x + cos 4x +···+cos 2nx) 2<br />

= n + ∑<br />

(2 sin 2lx sin 2kx + 2 cos 2lx cos 2kx)<br />

= n + 2<br />

1≤l

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