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Michael Corral: Vector Calculus

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4.4 Surface Integrals and the Divergence Theorem 161<br />

is a parametrization ofΣover R (since z=1−(x+y) onΣ). So onΣ,<br />

( 1√3<br />

f·n=(yz,xz,xy)· ,<br />

1<br />

√<br />

3<br />

,<br />

1<br />

√<br />

3<br />

)= 1 √<br />

3<br />

(yz+ xz+ xy)<br />

= 1 √<br />

3<br />

((x+y)z+ xy)= 1 √<br />

3<br />

((u+v)(1−(u+v))+uv)<br />

= 1 √<br />

3<br />

((u+v)−(u+v) 2 +uv)<br />

for (u,v) in R, and for r(u,v)= x(u,v)i+y(u,v)j+z(u,v)k=ui+vj+(1−(u+v))k we have<br />

∂r<br />

∂u ×∂r ∂v = (1,0,−1)×(0,1,−1)=(1,1,1) ⇒<br />

∂r<br />

∥∂u ×∂r<br />

∂v∥ =√ 3.<br />

Thus, integrating over R using vertical slices (e.g. as indicated by the dashed line in<br />

Figure 4.4.5) gives<br />

<br />

Σ<br />

<br />

f·dσ=<br />

Σ<br />

f·ndσ<br />

<br />

= (f(x(u,v),y(u,v),z(u,v))·n)<br />

∂r<br />

∥∂u ×∂r<br />

∂v∥ dvdu<br />

=<br />

=<br />

=<br />

R<br />

∫ 1 ∫ 1−u<br />

0<br />

∫ 1<br />

0<br />

∫ 1<br />

0<br />

0<br />

1<br />

√<br />

3<br />

((u+v)−(u+v) 2 +uv) √ 3dvdu<br />

⎛<br />

⎜⎝ (u+v)2 − (u+v)3<br />

2 3<br />

( 1<br />

6 + u 2 − 3u2<br />

2 + 5u3<br />

6<br />

∣1<br />

= u 6 + u2<br />

4 − u3<br />

2 + 5u4<br />

24<br />

∣<br />

0<br />

+ uv2<br />

2 ∣<br />

)<br />

du<br />

= 1 8 .<br />

v=1−u<br />

v=0<br />

⎞<br />

⎟⎠ du<br />

Computing surface integrals can often be tedious, especially when the formula for<br />

theoutwardunitnormalvectorateachpointofΣchanges. Thefollowingtheoremprovides<br />

an easier way in the case whenΣis a closed surface, that is, whenΣencloses<br />

a bounded solid in 3 . For example, spheres, cubes, and ellipsoids are closed surfaces,<br />

but planes and paraboloids are not.

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