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Michael Corral: Vector Calculus

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1.7 Curvilinear Coordinates 49<br />

Sometimes the equation of a surface in Cartesian coordinates can be transformed<br />

into a simpler equation in some other coordinate system, as in the following example.<br />

Example1.32. Writetheequationofthecylinder x 2 +y 2 = 4incylindricalcoordinates.<br />

Solution: Since r= √ x 2 +y 2 , then the equation in cylindrical coordinates is r=2.<br />

Using spherical coordinates to write the equation of a sphere does not necessarily<br />

make the equation simpler, if the sphere is not centered at the origin.<br />

Example 1.33. Write the equation (x−2) 2 +(y−1) 2 +z 2 = 9 in spherical coordinates.<br />

Solution: Multiplying the equation out gives<br />

x 2 +y 2 +z 2 −4x−2y+5=9,so we get<br />

ρ 2 −4ρsinφ cosθ−2ρsinφ sinθ−4=0,or<br />

ρ 2 −2sinφ(2cosθ−sinθ)ρ−4=0<br />

after combining terms. Note that this actually makes it more difficult to figure out<br />

what the surface is, as opposed to the Cartesian equation where you could immediately<br />

identify the surface as a sphere of radius 3 centered at (2,1,0).<br />

Example 1.34. Describe the surface given byθ=zin cylindrical coordinates.<br />

Solution: This surface is called a helicoid. As the (vertical) z coordinate increases,<br />

so does the angleθ, while the radius r is unrestricted. So this sweeps out a (ruled!)<br />

surface shaped like a spiral staircase, where the spiral has an infinite radius. Figure<br />

1.7.6 shows a section of this surface restricted to 0≤z≤4π and 0≤r≤2.<br />

14<br />

12<br />

10<br />

8<br />

z<br />

6<br />

4<br />

2<br />

0 -2<br />

-1.5<br />

-1<br />

-0.5<br />

y<br />

0<br />

0.5<br />

1<br />

1.5<br />

2<br />

2<br />

1<br />

1.5<br />

0<br />

0.5<br />

-1<br />

-0.5<br />

-2<br />

-1.5<br />

x<br />

Figure 1.7.6 Helicoidθ=z

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