21.04.2014 Views

Michael Corral: Vector Calculus

Michael Corral: Vector Calculus

Michael Corral: Vector Calculus

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

14 CHAPTER 1. VECTORS IN EUCLIDEAN SPACE<br />

We can now easily prove Theorem 1.1 from the previous section. The distance d<br />

between two points P=(x 1 ,y 1 ,z 1 ) and Q=(x 2 ,y 2 ,z 2 ) in 3 is the same as the length<br />

of the vector w−v, where the vectors v and w are defined as v=(x 1 ,y 1 ,z 1 ) and w=<br />

(x 2 ,y 2 ,z 2 ) (see Figure 1.2.8). So since w−v=(x 2 − x 1 ,y 2 −y 1 ,z 2 −z 1 ), then d=‖w−v‖=<br />

√<br />

(x2 − x 1 ) 2 +(y 2 −y 1 ) 2 +(z 2 −z 1 ) 2 by Theorem 1.2.<br />

x<br />

0<br />

z<br />

v<br />

P(x 1 ,y 1 ,z 1 )<br />

w<br />

w−v<br />

Q(x 2 ,y 2 ,z 2 )<br />

y<br />

Figure 1.2.8 Proof of Theorem 1.2: d=‖w−v‖<br />

A<br />

☛ ✟<br />

✡Exercises<br />

✠<br />

1. Let v=(−1,5,−2) and w=(3,1,1).<br />

(a) Find v−w. (b) Find v+w. (c) Find v<br />

‖v‖ . (d) Find∥ ∥ ∥<br />

1<br />

2 (v−w)∥ ∥ ∥.<br />

(e) Find ∥ ∥ ∥<br />

1<br />

2 (v+w)∥ ∥ ∥. (f) Find−2v+4w. (g) Find v−2w.<br />

(h) Find the vector u such that u+v+w=i.<br />

(i) Find the vector u such that u+v+w=2j+k.<br />

(j) Is there a scalar m such that m(v+2w)=k? If so, find it.<br />

2. For the vectors v and w from Exercise 1, is‖v−w‖=‖v‖−‖w‖? If not, which<br />

quantity is larger?<br />

3. For the vectors v and w from Exercise 1, is‖v+w‖=‖v‖+‖w‖? If not, which<br />

quantity is larger?<br />

B<br />

4. Prove Theorem 1.5(f) for 3 . 5. Prove Theorem 1.5(g) for 3 .<br />

C<br />

6. We know that every vector in 3 can be written as a scalar combination of the<br />

vectors i, j, and k. Can every vector in 3 be written as a scalar combination of<br />

just i and j, i.e. for any vector v in 3 , are there scalars m, n such that v=mi+nj?<br />

Justify your answer.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!