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Michael Corral: Vector Calculus

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191<br />

Section 2.7 (p. 100)<br />

( ( )<br />

−4<br />

1. min. √, −2 √<br />

); max. √<br />

4, √5<br />

2<br />

( 5 5<br />

( 5<br />

20<br />

3. min. √<br />

30<br />

, √<br />

); max. − 20<br />

13 13<br />

4. min.<br />

5. 8abc<br />

3 √ 3<br />

Chapter 3<br />

(<br />

−9<br />

√<br />

5<br />

,0,<br />

2 √5<br />

); max.<br />

Section 3.1 (p. 104)<br />

)<br />

√ ,−√ 30<br />

13 13<br />

( √<br />

9<br />

8 , 59<br />

4 ,−1 4<br />

1. 1 3.<br />

7<br />

12<br />

5. 7 6<br />

7. 5 9. 1 2<br />

11. 15<br />

Section 3.2 (p. 109)<br />

1. 1 3. 8ln2−3 5. π 4<br />

6. 1 4<br />

7. 2 9. 1 6<br />

10. 6 5<br />

Section 3.3 (p. 112)<br />

9<br />

1.<br />

2<br />

3. (2cos(π 2 )+π 4 1<br />

− 2)/4 5.<br />

6<br />

7. 6<br />

10. 1 3<br />

Section 3.4 (p. 116)<br />

1. The values should converge to≈1.318.<br />

(Hint: In Java the exponential function<br />

e x can be obtained with Math.exp(x).<br />

Other languages have similar functions,<br />

otherwise use e = 2.7182818284590455 in<br />

your program.)<br />

2.≈ 1.146 3.≈ 0.705 4.≈ 0.168<br />

Section 3.5 (p. 123)<br />

1. 8π 3. 4π 3 (8−33/2 ) 7. 1− sin2<br />

2<br />

9. 2πab<br />

Section 3.6 (p. 127)<br />

1. (1,8/3) 3. (0, 4a<br />

3π<br />

) 5. (0,3π/16)<br />

7. (0,0,5a/12) 9. (7/12,7/12,7/12)<br />

)<br />

Section 3.7 (p. 134)<br />

1. √ π 2. 1 6. Both are<br />

n<br />

(n+1) 2 (n+2)<br />

Chapter 4<br />

Section 4.1 (p. 142)<br />

1. 1/2 3. 23 5. 24π 7.−2π 9. 2π<br />

11. 4π<br />

Section 4.2 (p. 149)<br />

7. 1 n<br />

1. 0 3. No 4. Yes. F(x,y)= x2<br />

2 − y2<br />

2<br />

5. No 9. (b) No. Hint: Think of how F is<br />

defined. 10. Yes. F(x,y)=axy+bx+cy+d<br />

Section 4.3 (p. 155)<br />

1. 16/15 3.−5π 5. Yes. F(x,y)= xy 2 + x 3<br />

7. Yes. F(x,y)=4x 2 y+2y 2 +3x<br />

Section 4.4 (p. 163)<br />

1. 216π 2. 3 3. 12π/5 7. 15/4<br />

Section 4.5 (p. 175)<br />

1. 2 √ 2π 2 2. (17 √ 17−5 √ 5)/3 3. 2/5<br />

4. 1 5. 2π(π−1) 7. 67/15 9. 6<br />

11. Yes 13. No 19. Hint: Think of<br />

howavectorfieldf(x,y)=P(x,y)i+Q(x,y)j<br />

in 2 can be extended in a natural way to<br />

be a vector field in 3 .<br />

Section 4.6 (p. 186)<br />

1. 0 3. 12 √ x 2 +y 2 +z 2 5. 6(x+y+z)<br />

7. 12ρ 8. (4ρ 2 −6)e −ρ2 9.− 2z e<br />

r 3 r + 1 e<br />

r 2 z<br />

11. div f= 2 ρ − sinθ<br />

sinφ +cotφ;<br />

curl f=cotφ cosθe ρ +2e θ −2cosθe φ<br />

25. Hint: Start by showing that e r =<br />

cosθi+sinθj, e θ =−sinθi+cosθj, e z = k.

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