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Lectures on String Theory

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– 128 –<br />

D. Riemann normal coordinates<br />

C<strong>on</strong>sider a Riemannian manifold M of dimensi<strong>on</strong> n with coordinates x i , 1 = 1, . . . , m.<br />

The geodesic equati<strong>on</strong> is<br />

ẍ i + Γ i jk(x)ẋ j ẋ k = 0 .<br />

Let us c<strong>on</strong>sider two points p and q with coordinates x i and x i + δx i respectively. We<br />

assume that these points are closed so there is a unique geodesic c<strong>on</strong>necting them.<br />

A parameter t <strong>on</strong> the geodesic can be chosen proporti<strong>on</strong>al to the length of the<br />

arc c<strong>on</strong>necting these two points (the natural parameter). The soluti<strong>on</strong> x i (t) can be<br />

chosen so that x i (0) ≡ x i and x i (1) = x i + δx i . The tangent vector to the geodesic<br />

at t = 0 is defined by ξ i = ẋ i (0). Then equati<strong>on</strong> for the geodesic can be solved<br />

perturbatively by assuming the following expansi<strong>on</strong><br />

x i (t) = x i + c i 1t + c i 2t 2 + · · · .<br />

Plugging this into the geodesic equati<strong>on</strong> <strong>on</strong>e finds<br />

where<br />

x i (t) = x i + ξ i t − 1 2 Γi j 1 j 2<br />

(x)ξ j 1<br />

ξ j 2<br />

t 2 − 1 3! Γi j 1 j 2 j 3<br />

(x)ξ j 1<br />

ξ j 2<br />

ξ j 3<br />

t 3 − · · · ,<br />

Γ i j 1 j 2 j 3<br />

= ∂ j1 Γ i j 2 j 3<br />

− Γ l j 1 j 2<br />

Γ i lj 3<br />

− Γ l j 1 j 2<br />

Γ i j 3 l .<br />

Here all the quantities are evaluated at x i . At t = 1 we have x i (1) = x i + δx i so that<br />

x i + δx i = x i + ξ i − 1 2 Γi j 1 j 2<br />

(x)ξ j 1<br />

ξ j 2<br />

− 1 3! Γi j 1 j 2 j 3<br />

(x)ξ j 1<br />

ξ j 2<br />

ξ j 3<br />

− · · ·<br />

Hence, the point x i + δx i is parameterized by the tangent vector ξ i . We can therefore<br />

take ξ i as the new coordinate system <strong>on</strong> our manifold. The coordinates ξ i are<br />

called Riemann normal coordinates. They are used to define a map of an open<br />

neighbourhood U of the zero-vector 0 ∈ T x M to the manifold M:<br />

exp x :<br />

U ∈ T x M → M<br />

which is well-defined diffeomorphism of U <strong>on</strong> its image. Now we are parameterizing<br />

the points of the curved manifold with tangent vectors. The image of the geodesic<br />

through a point x in the Riemann normal coordinates is just a straight line.<br />

How metric will look in the new coordinate system? Up<strong>on</strong> changing the coordinates<br />

form x i to ξ i the metric transforms in the standard way<br />

We have<br />

g ij(ξ) ′ = ∂(xk + δx k ) ∂(x l + δx l )<br />

g<br />

∂ξ i ∂ξ j kl (x + δx)<br />

∂(x k + δx k )<br />

∂ξ i = δ k i − Γ k ijξ j + · · ·

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