Lectures on String Theory
Lectures on String Theory
Lectures on String Theory
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
– 132 –<br />
Exercise 10.<br />
• Show that the c<strong>on</strong>straints<br />
have the following Poiss<strong>on</strong> brackets<br />
C 1 = P µ P µ + T 2 X ′ µX ′µ , C 2 = P µ X ′µ<br />
{C 1 (σ), C 1 (σ ′ )} = 4T 2 ∂ σ C 2 (σ)δ(σ − σ ′ ) + 8T 2 C 2 (σ)∂ σ δ(σ − σ ′ ) ,<br />
{C 1 (σ), C 2 (σ ′ )} = ∂ σ C 1 (σ)δ(σ − σ ′ ) + 2C 1 (σ)∂ σ δ(σ − σ ′ ) ,<br />
{C 2 (σ), C 1 (σ ′ )} = ∂ σ C 1 (σ)δ(σ − σ ′ ) + 2C 1 (σ)∂ σ δ(σ − σ ′ ) ,<br />
{C 2 (σ), C 2 (σ ′ )} = ∂ σ C 2 (σ)δ(σ − σ ′ ) + 2C 2 (σ)∂ σ δ(σ − σ ′ ) .<br />
• Define the linear combinati<strong>on</strong>s<br />
T ++ = 1<br />
8T 2 (C 1 + 2T C 2 ) = 1<br />
8T 2 (P µ + T X ′ µ) 2 ,<br />
T −− = 1<br />
8T 2 (C 1 − 2T C 2 ) = 1<br />
8T 2 (P µ − T X ′ µ) 2 .<br />
and show that their Poiss<strong>on</strong> algebra is<br />
{T ++ (σ), T ++ (σ ′ )} = 1 (<br />
)<br />
∂ σ T ++ (σ)δ(σ − σ ′ ) + 2T ++ (σ)∂ σ δ(σ − σ ′ ) ,<br />
2T<br />
{T −− (σ), T −− (σ ′ )} = − 1 (<br />
)<br />
∂ σ T −− (σ)δ(σ − σ ′ ) + 2T −− (σ)∂ σ δ(σ − σ ′ ) ,<br />
2T<br />
{T ++ (σ), T −− (σ ′ )} = 0 .<br />
Exercise 11. For the closed string case define<br />
L m = 2T<br />
¯L m = 2T<br />
∫ 2π<br />
0<br />
∫ 2π<br />
0<br />
dσ e imσ− T −− (σ, τ)<br />
dσ e imσ+ T ++ (σ, τ) .<br />
Show that for any integer m the generators L m and ¯L m are time-independent.<br />
Exercise 12. Compute the Poiss<strong>on</strong> brackets of the c<strong>on</strong>straints L m , ¯L m . What<br />
kind of c<strong>on</strong>straints they are, i.e. the first or the sec<strong>on</strong>d class?<br />
Exercise 13. It is known in curved space-time that we can transform the metric<br />
locally in the neighborhood of a point x µ = 0 to the following form g µν (x) = η µν −