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Lectures on String Theory

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– 132 –<br />

Exercise 10.<br />

• Show that the c<strong>on</strong>straints<br />

have the following Poiss<strong>on</strong> brackets<br />

C 1 = P µ P µ + T 2 X ′ µX ′µ , C 2 = P µ X ′µ<br />

{C 1 (σ), C 1 (σ ′ )} = 4T 2 ∂ σ C 2 (σ)δ(σ − σ ′ ) + 8T 2 C 2 (σ)∂ σ δ(σ − σ ′ ) ,<br />

{C 1 (σ), C 2 (σ ′ )} = ∂ σ C 1 (σ)δ(σ − σ ′ ) + 2C 1 (σ)∂ σ δ(σ − σ ′ ) ,<br />

{C 2 (σ), C 1 (σ ′ )} = ∂ σ C 1 (σ)δ(σ − σ ′ ) + 2C 1 (σ)∂ σ δ(σ − σ ′ ) ,<br />

{C 2 (σ), C 2 (σ ′ )} = ∂ σ C 2 (σ)δ(σ − σ ′ ) + 2C 2 (σ)∂ σ δ(σ − σ ′ ) .<br />

• Define the linear combinati<strong>on</strong>s<br />

T ++ = 1<br />

8T 2 (C 1 + 2T C 2 ) = 1<br />

8T 2 (P µ + T X ′ µ) 2 ,<br />

T −− = 1<br />

8T 2 (C 1 − 2T C 2 ) = 1<br />

8T 2 (P µ − T X ′ µ) 2 .<br />

and show that their Poiss<strong>on</strong> algebra is<br />

{T ++ (σ), T ++ (σ ′ )} = 1 (<br />

)<br />

∂ σ T ++ (σ)δ(σ − σ ′ ) + 2T ++ (σ)∂ σ δ(σ − σ ′ ) ,<br />

2T<br />

{T −− (σ), T −− (σ ′ )} = − 1 (<br />

)<br />

∂ σ T −− (σ)δ(σ − σ ′ ) + 2T −− (σ)∂ σ δ(σ − σ ′ ) ,<br />

2T<br />

{T ++ (σ), T −− (σ ′ )} = 0 .<br />

Exercise 11. For the closed string case define<br />

L m = 2T<br />

¯L m = 2T<br />

∫ 2π<br />

0<br />

∫ 2π<br />

0<br />

dσ e imσ− T −− (σ, τ)<br />

dσ e imσ+ T ++ (σ, τ) .<br />

Show that for any integer m the generators L m and ¯L m are time-independent.<br />

Exercise 12. Compute the Poiss<strong>on</strong> brackets of the c<strong>on</strong>straints L m , ¯L m . What<br />

kind of c<strong>on</strong>straints they are, i.e. the first or the sec<strong>on</strong>d class?<br />

Exercise 13. It is known in curved space-time that we can transform the metric<br />

locally in the neighborhood of a point x µ = 0 to the following form g µν (x) = η µν −

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