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Linear Algebra

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206 Chapter 3. Maps Between Spaces<br />

then h1 : R 2 → R 2 represented by H with respect to B1,D1 maps<br />

� � � �<br />

c1 c1<br />

=<br />

c2<br />

c2<br />

B1<br />

↦→<br />

� �<br />

c1<br />

0<br />

D1<br />

=<br />

� �<br />

c1<br />

0<br />

while h2 : R 2 → R 2 represented by H with respect to B2,D2 is this map.<br />

� � � �<br />

c1 c2<br />

=<br />

c2<br />

c1<br />

B2<br />

↦→<br />

� �<br />

c2<br />

0<br />

D2<br />

� �<br />

0<br />

=<br />

These two are different. The first is projection onto the x axis, while the second<br />

is projection onto the y axis.<br />

So not only is any linear map described by a matrix but any matrix describes<br />

a linear map. This means that we can, when convenient, handle linear maps<br />

entirely as matrices, simply doing the computations, without have to worry that<br />

a matrix of interest does not represent a linear map on some pair of spaces of<br />

interest. (In practice, when we are working with a matrix but no spaces or<br />

bases have been specified, we will often take the domain and codomain to be R n<br />

and R m and use the standard bases. In this case, because the representation<br />

is transparent—the representation with respect to the standard basis of �v is<br />

�v—the column space of the matrix equals the range of the map. Consequently,<br />

the column space of H is often denoted by R(H).)<br />

With the theorem, we have characterized linear maps as those maps that act<br />

in this matrix way. Each linear map is described by a matrix and each matrix<br />

describes a linear map. We finish this section by illustrating how a matrix can<br />

be used to tell things about its maps.<br />

2.3 Theorem The rank of a matrix equals the rank of any map that it represents.<br />

Proof. Suppose that the matrix H is m×n. Fix domain and codomain spaces<br />

V and W of dimension n and m, with bases B = 〈 � β1,..., � βn〉 and D. Then H<br />

represents some linear map h between those spaces with respect to these bases<br />

whose rangespace<br />

{h(�v) � � �v ∈ V } = {h(c1 � β1 + ···+ cn � βn) � � c1,...,cn ∈ R}<br />

= {c1h( � β1)+···+ cnh( � βn) � � c1,...,cn ∈ R}<br />

is the span [{h( � β1),...,h( � βn)}]. The rank of h is the dimension of this rangespace.<br />

The rank of the matrix is its column rank (or its row rank; the two are<br />

equal). This is the dimension of the column space of the matrix, which is the<br />

span of the set of column vectors [{Rep D(h( � β1)),...,Rep D(h( � βn))}].<br />

To see that the two spans have the same dimension, recall that a representation<br />

with respect to a basis gives an isomorphism Rep D : W → R m . Under<br />

this isomorphism, there is a linear relationship among members of the rangespace<br />

if and only if the same relationship holds in the column space, e.g, �0 =<br />

c2

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