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Linear Algebra

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78 Chapter 1. <strong>Linear</strong> Systems<br />

parallel pair can be said to be equivalent to a single resistor having a value of<br />

20/(25/6) = 24/5 =4.8 ohms.<br />

(a) What is the equivalent resistance if the two resistors in parallel are 8 ohms<br />

and 5 ohms? Has the equivalent resistance risen or fallen?<br />

(b) What is the equivalent resistance if the two are both 8 ohms?<br />

(c) Find the formula for the equivalent resistance R if the two resistors in parallel<br />

are R1 ohms and R2 ohms.<br />

(d) What is the formula for more than two resistors in parallel?<br />

6 In the car dashboard example that begins the discussion, solve for these amperages.<br />

Assume all resistances are 15 ohms.<br />

(a) If the driver is stepping on the brakes, so the brake lights are on, and no<br />

other circuit is closed.<br />

(b) If all the switches are closed (suppose both the high beams and the low beams<br />

rate 15 ohms).<br />

7 Show that, in the Wheatstone Bridge, if r2r6 = r3r5 then i4 =0. (Thewaythis<br />

device is used in practice is that an unknown resistance, say at r1, iscompared<br />

to three known resistances. At r3 is placed a meter that shows the current. The<br />

known resistances are varied until the current is read as 0, and then from the above<br />

equation the value of the resistor at r1 can be calculated.)

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