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Linear Algebra

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Topic: Projective Geometry 339<br />

P P P<br />

There are two awkward things about this situation. The first is that neither of<br />

the two points in the domain nearest to the vertical dotted line (see below) has<br />

an image because a projection from those two is along the dotted line that is<br />

parallel to the codomain plane (we sometimes say that these two are projected<br />

“to infinity”). The second awkward thing is that the vanishing point in I isn’t<br />

the image of any point from S because a projection to this point would be along<br />

the dotted line that is parallel to the domain plane (we sometimes say that the<br />

vanishing point is the image of a projection “from infinity”).<br />

For a better model, put the projector P at the origin. Imagine that P is<br />

covered by a glass hemispheric dome. As P looks outward, anything in the line<br />

of vision is projected to the same spot on the dome. This includes things on<br />

the line between P and the dome, as in the case of projection by the movie<br />

projector. It includes things on the line further from P than the dome, as in<br />

the case of projection by the painter. It also includes things on the line that lie<br />

behind P , as in the case of projection by a pinhole.<br />

ℓ = {k ·<br />

� �<br />

1 ��<br />

2 k ∈ R}<br />

3<br />

From this perspective P , all of the spots on the line are seen as the same point.<br />

Accordingly, for any nonzero vector �v ∈ R3 , we define the associated point v<br />

in the projective plane to be the set {k�v � � k ∈ R and k �= 0} of nonzero vectors<br />

lying on the same line through the origin as �v. To describe a projective point<br />

we can give any representative member of the line, so that the projective point<br />

shown above can be represented in any of these three ways.<br />

⎛<br />

⎝ 1<br />

⎞ ⎛<br />

2⎠<br />

⎝<br />

3<br />

1/3<br />

⎞ ⎛<br />

2/3⎠<br />

⎝<br />

1<br />

−2<br />

⎞<br />

−4⎠<br />

−6

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