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Linear Algebra

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Section III. Other Formulas 329<br />

1.9 Theorem Where T is a square matrix, T · adj(T )=adj(T ) · T = |T |·I.<br />

Proof. Equations (∗) and (∗∗). QED<br />

1.10 Example If<br />

⎛<br />

1<br />

T = ⎝2 0<br />

1<br />

⎞<br />

4<br />

−1⎠<br />

1 0 1<br />

then the adjoint adj(T )is<br />

⎛<br />

T1,1<br />

⎝T1,2<br />

T1,3<br />

T2,1<br />

T2,2<br />

T2,3<br />

⎛ �<br />

�<br />

�1<br />

⎞ ⎜ �<br />

⎜ 0<br />

T3,1 ⎜<br />

T3,2⎠=<br />

⎜<br />

T3,3 ⎜<br />

⎝<br />

�<br />

−1�<br />

�<br />

1 � −<br />

�<br />

�<br />

− �2<br />

�1 �<br />

−1�<br />

�<br />

1 �<br />

�<br />

�<br />

�0<br />

�0 �<br />

�<br />

�1<br />

�1 �<br />

4�<br />

�<br />

1�<br />

�<br />

4�<br />

�<br />

1�<br />

�<br />

�<br />

�0<br />

�1 �<br />

4 �<br />

�<br />

−1�<br />

−<br />

�<br />

�<br />

�2<br />

�1 �<br />

1�<br />

�<br />

0�<br />

�<br />

�<br />

− �1<br />

�1 �<br />

0�<br />

�<br />

0�<br />

�<br />

�<br />

�1<br />

�2 �<br />

�<br />

�1<br />

�2 ⎞<br />

⎟<br />

�⎟<br />

⎛<br />

4 �⎟<br />

1<br />

�⎟<br />

−1�⎟=<br />

⎝−3<br />

⎟<br />

� ⎟ −1<br />

0�⎠<br />

�<br />

1�<br />

0<br />

−3<br />

0<br />

⎞<br />

−4<br />

9 ⎠<br />

1<br />

and taking the product with T gives the diagonal matrix |T |·I.<br />

⎛<br />

1<br />

⎝2<br />

0<br />

1<br />

⎞ ⎛<br />

4 1<br />

−1⎠<br />

⎝−3<br />

0<br />

−3<br />

⎞ ⎛<br />

−4 −3<br />

9 ⎠ = ⎝ 0<br />

0<br />

−3<br />

⎞<br />

0<br />

0 ⎠<br />

1 0 1 −1 0 1 0 0 −3<br />

1.11 Corollary If |T |�= 0 then T −1 =(1/|T |) · adj(T ).<br />

1.12 Example The inverse of the matrix from Example 1.10 is (1/−3)·adj(T ).<br />

T −1 ⎛<br />

1/−3<br />

= ⎝−3/−3<br />

0/−3<br />

−3/−3<br />

⎞ ⎛<br />

−4/−3 −1/3<br />

9/−3⎠<br />

= ⎝ 1<br />

0<br />

1<br />

⎞<br />

4/3<br />

−3 ⎠<br />

−1/−3 0/−3 1/−3 1/3 0 −1/3<br />

The formulas from this section are often used for by-hand calculation and<br />

are sometimes useful with special types of matrices. However, they are not the<br />

best choice for computation with arbitrary matrices because they require more<br />

arithmetic than, for instance, the Gauss-Jordan method.<br />

Exercises<br />

� 1.13 Find the cofactor.<br />

T =<br />

�<br />

1 0<br />

�<br />

2<br />

−1 1 3<br />

0 2 −1<br />

(a) T2,3 (b) T3,2 (c) T1,3<br />

� 1.14 Find the determinant by expanding<br />

�<br />

� 3 0<br />

�<br />

� 1 2<br />

�<br />

−1 3<br />

�<br />

1�<br />

�<br />

2�<br />

0<br />

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