Practical Poker Math

contain an Ace, and multiply that number by the number of
remaining unseen Aces, resulting in the total number of possible
3-card combinations that will contain at least an Ace.
Subtract the 2 cards in the hole and the 3 remaining Aces,
leaving 47 unseen cards none of which are Aces, then use
Comb(47, 2):
(47 * 46) = 1,081
(1 * 2)
With 1,081 possible 2-card combinations that contain no
Aces and 3 remaining Aces unseen, the number of possible
3-card Flops that WILL flop at least a pair of Aces is
3 * 1,081 = 3,243
We now have all the numbers needed to calculate the odds of
flopping at least a pair of Aces with AJ in the hole:
Total Possibilities = 19,600
– WILLs = 3,243
WILLNOTs = 16,357
Odds of Flopping at Least AA
WILLNOTs : WILLs
16,357 : 3,243
Reduce
16,357 / 3,243 : 3,243 / 3,243
5 : 1
2 Unpaired Hole Cards >>> Pair Either Hole Card
To find the odds of flopping at least a Pair of either hole card
89
Before the Flop