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Practical Poker Math

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3. Odds in Texas Hold’em<br />

2 Unpaired Hole Cards >>> Flop a Set<br />

To find the odds of a Flop that will include either a pair of<br />

Aces or a pair of Jacks with AJ in the hole, we need to know<br />

the number of possible Pairs of both Aces and Jacks from the<br />

remaining 3 Aces and 3 Jacks:<br />

(3 * 2) = 3<br />

(1 * 2)<br />

With 3 possible pairs of Aces and 3 possible pairs of Jacks<br />

there are 6 different Pairs that can appear as part of the Flop<br />

to make a Set to either hole card.<br />

Minus the 2 cards in the hole and the 6 remaining Aces and<br />

Jacks there are 44 unseen cards, none of which are Aces or Jacks.<br />

With 6 possible Pairs and 44 unseen cards that are not either<br />

an Ace or a Jack, the number of possible 3-card Flops that<br />

WILL flop a not-too-hidden Set of either hole card is:<br />

6 * 44 = 264<br />

We now have all the numbers needed to calculate the odds of<br />

flopping a Set to either hole card:<br />

Total Possibilities = 19,600<br />

– WILLs = 264<br />

WILLNOTs = 19,336<br />

Odds of Flopping a Set<br />

WILLNOTs : WILLs<br />

19,336 : 264<br />

Reduce<br />

19,336 / 264 : 264 / 264<br />

73.24 : 1<br />

92

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