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Practical Poker Math

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3. Odds in Texas Hold’em<br />

with AJ in the hole, find the number of 2-card combinations<br />

that do not contain either an Ace or a Jack, multiply that<br />

number by the number of remaining unseen Aces and Jacks,<br />

giving you the total number of possible 3-card combinations<br />

that will contain at least one Ace or one Jack.<br />

Subtract the 2 cards in the hole and the 6 remaining Aces<br />

and Jacks, leaving 44 unseen cards none of which are Aces or<br />

Jacks, then use Comb(44, 2):<br />

(44 * 43) = 946<br />

(1 * 2)<br />

With 946 possible 2-card combinations that contain no Aces<br />

or Jacks plus 6 remaining Aces and Jacks, the number of possible<br />

3-card Flops that WILL flop at least a pair of Aces or a<br />

pair of Jacks is<br />

6 * 946 = 5,676<br />

We now have all the numbers needed to calculate the odds of<br />

flopping at least a Pair of either Aces or Jacks with AJ in the<br />

hole:<br />

Total Possibilities = 19,600<br />

– WILLs = 5,676<br />

WILLNOTs = 13,924<br />

Odds of Flopping AA or JJ<br />

WILLNOTs : WILLs<br />

13,924 : 5,676<br />

Reduce<br />

13,924 / 5,676 : 5,676 / 5,676<br />

2.45 : 1<br />

90

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