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Practical Poker Math

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2 Unpaired Hole Cards >>> Pair Both Hole Cards<br />

on the Flop<br />

To find the odds of a Flop that will pair both hole cards with<br />

AJ in the hole, we know that 2 of the 3 Flop cards must be<br />

AJ. Find the number of possible AJ 2-card combinations<br />

from the remaining 3 Jacks and 3 Aces:<br />

3 * 3 = 9<br />

Minus the 2 cards in the hole and the 6 remaining Aces and<br />

Jacks there are 44 unseen cards, none of which are Aces or Jacks.<br />

With 9 possible 2-card combinations that contain both an<br />

Ace and a Jack and 44 unseen cards that are neither an Ace<br />

or a Jack, the number of possible 3-card Flops that WILL<br />

contain at least one Ace and one Jack is<br />

9 * 44 = 396<br />

We now have all the numbers needed to calculate the odds of<br />

flopping both a pair of Aces and a pair of Jacks with AJ in the<br />

hole:<br />

Total Possibilities = 19,600<br />

– WILLs = 396<br />

WILLNOTs = 19,204<br />

Odds of a Flop That Pairs Both Hole Cards<br />

WILLNOTs : WILLs<br />

19,204 : 396<br />

Reduce<br />

19,204 / 396 : 396 / 396<br />

48.49 : 1<br />

91<br />

Before the Flop

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