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Practical Poker Math

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3. Odds in Texas Hold’em<br />

Pocket Aces<br />

There are 6 different 2-card combinations that WILL contain<br />

a pair of Aces — Comb(4, 2):<br />

The number of 2-card combinations that WILL NOT contain<br />

a pair of Aces is Total Possibilities (1,326) — WILLs (6) =<br />

1,320 WILLNOTs.<br />

The odds against being dealt Aces in the hole in Hold’em are:<br />

WILLNOTs (1,320) : WILLs (6)<br />

1,320 : 6<br />

Reduce<br />

1,320 / 6 : 6 / 6<br />

220 : 1<br />

Another way is to determine the probability of being dealt<br />

Aces in the hole, by multiplying the probability of being dealt<br />

the first Ace by the probability of being dealt the second Ace:<br />

54

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