Technical details System pro M compactÂ®

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Systempro M compact ®Technical detailsAccessories for measurementinstrumentsMeasurementdevicesSelf-consumption of copper cables between the device and the transformerFor 5 A secondaryCable sectionmm 21.52.54610Power (two-pole cable) VAVADistance1 m 2 m 4 m 6 m 8 m 10 m0.58 1.15 2.31 3.46 4.62 5.770.36 0.71 1.43 2.14 2.86 3.570.22 0.45 0.89 1.34 1.79 2.240.15 0.30 0.60 1.89 1.19 1.490.09 0.18 0.36 0.54 0.71 0.89For 1A secondaryCable sectionmm 211.52.54610Power (two-pole cable) VAVADistance10 m 20 m 40 m 60 m 80 m 100 m0.36 0.71 1.43 2.14 2.85 3.570.23 0.46 0.92 1.39 1.85 2.310.14 0.29 0.57 0.86 1.14 1.430.09 0.18 0.36 0.54 0.71 0.890.06 0.12 0.24 0.36 0.48 0.600.04 0.07 0.14 0.21 0.29 0.36Maximum load (A) on copper bars accordingto DIN 43670 and 43671Bar dimensionsRated current (In) Amm 1 bar 2 bars 3 bars20x5 325 56020x10 427 925 118030x5 379 672 89630x10 573 1060 148040x5 482 836 109040x10 715 1290 177050x10 852 1510 204060x10 985 1720 230080x10 1240 2110 2790100x10 1490 2480 326011Rating Ratio fault limit in %0.05 In 0.2 In In 1.2 In0.5 ±1 ±0.75 ±0.5 ±0.51 ±2 ±1.5 ±1 ±13 From 0.5 In to 1.2 In = ± 3Rating Angle fault limit in %0.05 In 0.2 In In 1.2 In0.5 ±1.8 ±1.35 ±0.9 ±0.91 ±3.6 ±2.7 ±1.8 ±1.83 No prescriptionsAccuracy rating- 0.5 rating is required for power meters.- 1 rating is required for unoffi cial power measuresand power meters (measurements within thefi rm).- 3 rating is required for relays and protectiondevices.According to DIN 185, VDE-0414 and UNIE-21028 current and angle fault limits shall complywith the value shown in the table.11/104 ABB
Systempro M compact ®Technical detailsAccessories for measurementinstrumentsMeasurementdevicesFAULT CURVESF %543210-1-2-3-4-5-6-7-8-9-10-11-12-13-14-15Rated currentOvercurrent in protection transformersOvercurrent in measurementtransformers up to Sf 5NxRated current0,05 0,1 0,2 1 1,2 2 3 4 5 6 7 8 9 10Magnetic saturationFs 5 10 P5 10 P10Curve at 1/4 of rated impedanceRated impedance curveCable diameter calculationThe following formula applies for determining the diameters of a 95 mm 2 cable:- section=rxrx3.14 that is r 2 x3.14 from which r=√ section/3.14 r=√ 95/3.14=30.25=5.5 mm, so theradius is 5.5 mm- diameter=r+r so the diameter is 5.5+5.5 mm=11 mm (copper diameter to be added to the insulatingmaterial thickness, total ø about 20 mm).With many insertion of the cable into the current transformer it is possible to halve the primary currentwhile performance and rating values remain unaltered.Example11ABB11/105
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Technical details System pro M compactÂ®

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