12.07.2015 Views

Astroparticle Physics

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372 17 Solutions4.( ) 2R 0 t0 3= ,R mr t mrwhere R mr is the size of the universe at the time of matter–radiation equality t mr =50 000 a. With t 0 = 14 billion years, one hasR 0≈ 4280 .R mrThe size of the universe at that time wasR mr ≈ R 04280 ≈ 3.27 × 106 light-years ≈ 3.09 × 10 22 m .Extrapolating to earlier times requires to assume R ∼ √ t, since for times t

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