15.08.2015 Views

Introduction to the Modeling and Analysis of Complex Systems

introduction-to-the-modeling-and-analysis-of-complex-systems-sayama-pdf

introduction-to-the-modeling-and-analysis-of-complex-systems-sayama-pdf

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Chapter 7Continuous-Time Models II: <strong>Analysis</strong>7.1 Finding Equilibrium PointsFinding equilibrium points <strong>of</strong> a continuous-time model dx/dt = G(x) can be done in <strong>the</strong>same way as for a discrete-time model, i.e., by replacing all x’s with x eq ’s (again, note that<strong>the</strong>se could be vec<strong>to</strong>rs). This actually makes <strong>the</strong> left h<strong>and</strong> side zero, because x eq is nolonger a dynamical variable but just a static constant. Therefore, things come down <strong>to</strong> justsolving <strong>the</strong> following equation0 = G(x eq ) (7.1)with regard <strong>to</strong> x eq . For example, consider <strong>the</strong> following logistic growth model:dx(1dt = rx − x )K(7.2)Replacing all <strong>the</strong> x’s with x eq ’s, we obtain(0 = rx eq 1 − x )eq(7.3)Kx eq = 0, K (7.4)It turns out that <strong>the</strong> result is <strong>the</strong> same as that <strong>of</strong> its discrete-time counterpart (see Eq. (5.6)).Exercise 7.1Find <strong>the</strong> equilibrium points <strong>of</strong> <strong>the</strong> following model:dxdt = x2 − rx + 1 (7.5)111

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!