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Introduction to the Modeling and Analysis of Complex Systems

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18.6. MEAN-FIELD APPROXIMATION ON SCALE-FREE NETWORKS 423q n is <strong>the</strong> probability that a neighbor node is infected by <strong>the</strong> disease. Thus q n p i corresponds<strong>to</strong> <strong>the</strong> “something” part in Eq. (18.29). It can take any value between 0 <strong>and</strong> 1, but for ourpurpose <strong>of</strong> studying <strong>the</strong> epidemic threshold <strong>of</strong> infection probability, we can assume thatq n p i is small. Therefore, using <strong>the</strong> approximation (1 − x) k ≈ 1 − kx for small x again, <strong>the</strong>iterative map above becomesq t+1 (k) = (1 − q(k)) (1 − (1 − kq n p i )) + q(k)(1 − p r ) (18.37)= (1 − q(k))kq n p i + q(k) − q(k)p r = f(q(k)). (18.38)Then we can calculate <strong>the</strong> equilibrium state <strong>of</strong> <strong>the</strong> nodes with degree k as follows:q eq (k) = (1 − q eq (k))kq n p i + q eq (k) − q eq (k)p r (18.39)q eq (k)p r = kq n p i − kq n p i q eq (k) (18.40)q eq (k) =kq np ikq n p i + p r(18.41)We can apply this back <strong>to</strong> <strong>the</strong> definition <strong>of</strong> q n <strong>to</strong> find <strong>the</strong> actual equilibrium state:q n = 1 ∑k ′ P (k ′ k ′ q n p i)(18.42)〈k〉k ′ qk ′ n p i + p rClearly, q n = 0 (i.e., q eq (k) = 0 for all k) satisfies this equation, so <strong>the</strong> extinction <strong>of</strong> <strong>the</strong>disease is still an equilibrium state <strong>of</strong> this system. But what we are interested in is <strong>the</strong>equilibrium with q n ≠ 0 (i.e., q eq (k) > 0 for some k), where <strong>the</strong> disease continues <strong>to</strong> exist,<strong>and</strong> we want <strong>to</strong> know whe<strong>the</strong>r such a state is stable. To solve Eq. (18.42), we will need <strong>to</strong>assume a certain degree distribution P (k).For example, if we assume that <strong>the</strong> network is large <strong>and</strong> r<strong>and</strong>om, we can use <strong>the</strong>following crude approximate degree distribution:{ 1 if k = 〈k〉P (k) ≈(18.43)0 o<strong>the</strong>rwiseWe can use this approximation because, as <strong>the</strong> network size increases, <strong>the</strong> degree distribution<strong>of</strong> a r<strong>and</strong>om graph becomes more <strong>and</strong> more concentrated at <strong>the</strong> average degree(relative <strong>to</strong> <strong>the</strong> network size), due <strong>to</strong> <strong>the</strong> law <strong>of</strong> large numbers well known in statistics.Then Eq. (18.42) is solved as follows:q n =〈k〉q np i〈k〉q n p i + p r(18.44)〈k〉q n p i + p r = 〈k〉p i (18.45)q n = 1 −p r〈k〉p i(18.46)

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