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Introduction to the Modeling and Analysis of Complex Systems

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17.1. NETWORK SIZE, DENSITY, AND PERCOLATION 375We can calculate <strong>the</strong> network percolation threshold for r<strong>and</strong>om graphs as follows. Letq be <strong>the</strong> probability for a r<strong>and</strong>omly selected node <strong>to</strong> not belong <strong>to</strong> <strong>the</strong> largest connectedcomponent (LCC) <strong>of</strong> a network. If q < 1, <strong>the</strong>n <strong>the</strong>re is a giant component in <strong>the</strong> network. Inorder for a r<strong>and</strong>omly selected node <strong>to</strong> be disconnected from <strong>the</strong> LCC, all <strong>of</strong> its neighborsmust be disconnected from <strong>the</strong> LCC <strong>to</strong>o. Therefore, somewhat tau<strong>to</strong>logicallyq = q k , (17.4)where k is <strong>the</strong> degree <strong>of</strong> <strong>the</strong> node in question. But in general, degree k is not uniquely determinedin a r<strong>and</strong>om network, so <strong>the</strong> right h<strong>and</strong> side should be rewritten as an expectedvalue, as∞∑q = P (k)q k , (17.5)k=0where P (k) is <strong>the</strong> probability for <strong>the</strong> node <strong>to</strong> have degree k (called <strong>the</strong> degree distribution;this will be discussed in more detail later). In an Erdős-Rényi r<strong>and</strong>om graph, thisprobability can be calculated by <strong>the</strong> following binomial distribution⎧⎨P (k) =⎩( n − 1k)p k (1 − p) n−1−k for 0 ≤ k ≤ n − 1,0 for k ≥ n,(17.6)because each node has n − 1 potential neighbors <strong>and</strong> k out <strong>of</strong> n − 1 neighbors need <strong>to</strong>be connected <strong>to</strong> <strong>the</strong> node (<strong>and</strong> <strong>the</strong> rest need <strong>to</strong> be disconnected from it) in order for it <strong>to</strong>have degree k. By plugging Eq. (17.6) in<strong>to</strong> Eq. (17.5), we obtain∑n−1( ) n − 1q =p k (1 − p) n−1−k q k (17.7)kk=0∑n−1( ) n − 1=(pq) k (1 − p) n−1−k (17.8)kk=0= (pq + 1 − p) n−1 (17.9)= (1 + p(q − 1)) n−1 . (17.10)We can rewrite this as() n−1〈k〉(q − 1)q = 1 + , (17.11)nbecause <strong>the</strong> average degree 〈k〉 <strong>of</strong> an Erdős-Rényi graph for a large n is given by〈k〉 = np. (17.12)

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