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A First Course in Linear Algebra, 2017a

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134 Determ<strong>in</strong>ants<br />

The cofactor matrix is<br />

and so the <strong>in</strong>verse is<br />

⎡<br />

1<br />

⎣<br />

e t<br />

⎡<br />

C (t)= ⎣<br />

1 0 0<br />

0 e t cost e t s<strong>in</strong>t<br />

0 −e t s<strong>in</strong>t e t cost<br />

1 0 0<br />

0 e t cost e t s<strong>in</strong>t<br />

0 −e t s<strong>in</strong>t e t cost<br />

⎤<br />

⎦<br />

T<br />

⎡<br />

= ⎣<br />

⎤<br />

⎦<br />

e −t 0 0<br />

0 cost −s<strong>in</strong>t<br />

0 s<strong>in</strong>t cost<br />

⎤<br />

⎦<br />

♠<br />

3.2.2 Cramer’s Rule<br />

Another context <strong>in</strong> which the formula given <strong>in</strong> Theorem 3.40 is important is Cramer’s Rule. Recall that<br />

we can represent a system of l<strong>in</strong>ear equations <strong>in</strong> the form AX = B, where the solutions to this system<br />

are given by X. Cramer’s Rule gives a formula for the solutions X <strong>in</strong> the special case that A is a square<br />

<strong>in</strong>vertible matrix. Note this rule does not apply if you have a system of equations <strong>in</strong> which there is a<br />

different number of equations than variables (<strong>in</strong> other words, when A is not square), or when A is not<br />

<strong>in</strong>vertible.<br />

Suppose we have a system of equations given by AX = B, and we want to f<strong>in</strong>d solutions X which<br />

satisfy this system. Then recall that if A −1 exists,<br />

AX = B<br />

A −1 (AX) = A −1 B<br />

(<br />

A −1 A ) X = A −1 B<br />

IX = A −1 B<br />

X = A −1 B<br />

Hence, the solutions X to the system are given by X = A −1 B. S<strong>in</strong>ce we assume that A −1 exists, we can use<br />

the formula for A −1 given above. Substitut<strong>in</strong>g this formula <strong>in</strong>to the equation for X,wehave<br />

X = A −1 B = 1<br />

det(A) adj(A)B<br />

Let x i be the i th entry of X and b j be the j th entry of B. Then this equation becomes<br />

x i =<br />

n [ ] −1<br />

∑ aij b j =<br />

j=1<br />

n<br />

∑<br />

j=1<br />

1<br />

det(A) adj(A) ij b j<br />

where adj(A) ij is the ij th entry of adj(A).<br />

By the formula for the expansion of a determ<strong>in</strong>ant along a column,<br />

⎡<br />

⎤<br />

x i = 1 ∗ ··· b 1 ··· ∗<br />

det(A) det ⎢<br />

⎥<br />

⎣ . . . ⎦<br />

∗ ··· b n ··· ∗

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