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A First Course in Linear Algebra, 2017a

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260 R n 4<br />

3<br />

<strong>First</strong> we want to know the total time of the swim across the river. The velocity <strong>in</strong> the direction across<br />

the river is 3 kilometers per hour, and the river is 1 2<br />

kilometer wide. It follows the trip takes 1/6 hour or<br />

10 m<strong>in</strong>utes.<br />

Now, we can compute how far downstream he will end up. S<strong>in</strong>ce the river runs at a rate of 4 kilometers<br />

per hour, and the trip takes 1/6 hour, the distance traveled downstream is given by 4 ( )<br />

1<br />

6<br />

=<br />

2<br />

3<br />

kilometers.<br />

The distance traveled by the swimmer is given by the hypotenuse of a right triangle. The two arms of<br />

the triangle are given by the distance across the river, 1 2 km, and the distance traveled downstream, 2 3 km.<br />

Then, us<strong>in</strong>g the Pythagorean Theorem, we can calculate the total distance d traveled.<br />

√ (2<br />

3<br />

d =<br />

) 2 ( ) 1 2<br />

+ = 5 2 6 km<br />

Therefore, the swimmer travels a total distance of 5 6 kilometers.<br />

♠<br />

4.12.2 Work<br />

The mathematical concept of work is an application of vectors <strong>in</strong> R n . The physical concept of work differs<br />

from the notion of work employed <strong>in</strong> ord<strong>in</strong>ary conversation. For example, suppose you were to slide a<br />

150 pound weight off a table which is three feet high and shuffle along the floor for 50 yards, keep<strong>in</strong>g the<br />

height always three feet and then deposit this weight on another three foot high table. The physical concept<br />

of work would <strong>in</strong>dicate that the force exerted by your arms did no work dur<strong>in</strong>g this project. The reason<br />

for this def<strong>in</strong>ition is that even though your arms exerted considerable force on the weight, the direction of<br />

motion was at right angles to the force they exerted. The only part of a force which does work <strong>in</strong> the sense<br />

of physics is the component of the force <strong>in</strong> the direction of motion.<br />

Work is def<strong>in</strong>ed to be the magnitude of the component of this force times the distance over which it<br />

acts, when the component of force po<strong>in</strong>ts <strong>in</strong> the direction of motion. In the case where the force po<strong>in</strong>ts<br />

<strong>in</strong> exactly the opposite direction of motion work is given by (−1) times the magnitude of this component<br />

times the distance. Thus the work done by a force on an object as the object moves from one po<strong>in</strong>t to<br />

another is a measure of the extent to which the force contributes to the motion. This is illustrated <strong>in</strong> the<br />

follow<strong>in</strong>g picture <strong>in</strong> the case where the given force contributes to the motion.<br />

⃗F ⊥<br />

θ<br />

⃗F<br />

⃗F ||<br />

Q<br />

P<br />

Recall that for any vector ⃗u <strong>in</strong> R n ,wecanwrite⃗u as a sum of two vectors, as <strong>in</strong><br />

⃗u =⃗u || +⃗u ⊥

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