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A First Course in Linear Algebra, 2017a

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328 Complex Numbers<br />

Def<strong>in</strong>ition 6.10: Absolute Value<br />

The absolute value, or modulus, of a complex number, denoted |z| is def<strong>in</strong>ed as follows.<br />

√<br />

|a + bi| = a 2 + b 2<br />

Thus, if z is the complex number z = a + bi, it follows that<br />

|z| =(zz) 1/2<br />

Also from the def<strong>in</strong>ition, if z = a + bi and w = c + di are two complex numbers, then |zw| = |z||w|.<br />

Take a moment to verify this.<br />

The triangle <strong>in</strong>equality is an important property of the absolute value of complex numbers. There are<br />

two useful versions which we present here, although the first one is officially called the triangle <strong>in</strong>equality.<br />

Proposition 6.11: Triangle Inequality<br />

Let z,w be complex numbers.<br />

The follow<strong>in</strong>g two <strong>in</strong>equalities hold for any complex numbers z,w:<br />

The first one is called the Triangle Inequality.<br />

|z + w|≤|z| + |w|<br />

||z|−|w|| ≤ |z − w|<br />

Proof. Let z = a + bi and w = c + di. <strong>First</strong> note that<br />

and so |ac + bd|≤|zw| = |z||w|.<br />

zw =(a + bi)(c − di)=ac + bd +(bc − ad)i<br />

Then,<br />

|z + w| 2 =(a + c + i(b + d))(a + c − i(b + d))<br />

=(a + c) 2 +(b + d) 2 = a 2 + c 2 + 2ac + 2bd + b 2 + d 2<br />

≤|z| 2 + |w| 2 + 2|z||w| =(|z| + |w|) 2<br />

Tak<strong>in</strong>g the square root, we have that<br />

|z + w|≤|z| + |w|<br />

so this verifies the triangle <strong>in</strong>equality.<br />

To get the second <strong>in</strong>equality, write<br />

z = z − w + w, w = w − z + z<br />

and so by the first form of the <strong>in</strong>equality we get both:<br />

|z|≤|z − w| + |w|, |w|≤|z − w| + |z|

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