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A First Course in Linear Algebra, 2017a

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1.2. Systems of Equations, <strong>Algebra</strong>ic Procedures 15<br />

Def<strong>in</strong>ition 1.10: Augmented Matrix of a L<strong>in</strong>ear System<br />

For a l<strong>in</strong>ear system of the form<br />

a 11 x 1 + ···+ a 1n x n = b 1<br />

...<br />

a m1 x 1 + ···+ a mn x n = b m<br />

where the x i are variables and the a ij and b i are constants, the augmented matrix of this system is<br />

given by<br />

⎡<br />

⎤<br />

a 11 ··· a 1n b 1<br />

⎢<br />

⎥<br />

⎣<br />

...<br />

...<br />

... ⎦<br />

a m1 ··· a mn b m<br />

Now, consider elementary operations <strong>in</strong> the context of the augmented matrix. The elementary operations<br />

<strong>in</strong> Def<strong>in</strong>ition 1.6 can be used on the rows just as we used them on equations previously. Changes to<br />

a system of equations as a result of an elementary operation are equivalent to changes <strong>in</strong> the augmented<br />

matrix result<strong>in</strong>g from the correspond<strong>in</strong>g row operation. Note that Theorem 1.8 implies that any elementary<br />

row operations used on an augmented matrix will not change the solution to the correspond<strong>in</strong>g system of<br />

equations. We now formally def<strong>in</strong>e elementary row operations. These are the key tool we will use to f<strong>in</strong>d<br />

solutions to systems of equations.<br />

Def<strong>in</strong>ition 1.11: Elementary Row Operations<br />

The elementary row operations (also known as row operations) consist of the follow<strong>in</strong>g<br />

1. Switch two rows.<br />

2. Multiply a row by a nonzero number.<br />

3. Replace a row by any multiple of another row added to it.<br />

Recall how we solved Example 1.9. We can do the exact same steps as above, except now <strong>in</strong> the<br />

context of an augmented matrix and us<strong>in</strong>g row operations. The augmented matrix of this system is<br />

⎡<br />

1 3 6<br />

⎤<br />

25<br />

⎣ 2 7 14 58 ⎦<br />

0 2 5 19<br />

Thus the first step <strong>in</strong> solv<strong>in</strong>g the system given by 1.5 would be to take (−2) times the first row of the<br />

augmented matrix and add it to the second row,<br />

⎡<br />

1 3 6<br />

⎤<br />

25<br />

⎣ 0 1 2 8 ⎦<br />

0 2 5 19

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