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A First Course in Linear Algebra, 2017a

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278 L<strong>in</strong>ear Transformations<br />

The necessary augmented matrix and result<strong>in</strong>g reduced row-echelon form are given by:<br />

⎡ ⎤ ⎡ ⎤<br />

1 4 −7<br />

1 0 1<br />

⎣ 3 0 3 ⎦ →···→⎣<br />

0 1 −2 ⎦<br />

1 5 −9<br />

0 0 0<br />

Hence a = 1,b = −2 and<br />

⎡<br />

⎣<br />

−7<br />

3<br />

−9<br />

⎤<br />

⎡<br />

⎦ = 1⎣<br />

1<br />

3<br />

1<br />

⎤<br />

⎡<br />

⎦ +(−2) ⎣<br />

4<br />

0<br />

5<br />

⎤<br />

⎦<br />

Now, us<strong>in</strong>g the third property above, we have<br />

⎡ ⎤ ⎛ ⎡ ⎤ ⎡<br />

−7<br />

1<br />

T ⎣ 3 ⎦ = T ⎝1⎣<br />

3 ⎦ +(−2) ⎣<br />

−9<br />

1<br />

⎡ ⎤ ⎡ ⎤<br />

1 4<br />

= 1T ⎣ 3 ⎦ − 2T ⎣ 0 ⎦<br />

1 5<br />

⎡<br />

Therefore, T ⎣<br />

−7<br />

3<br />

−9<br />

⎤<br />

⎦ =<br />

⎡<br />

⎢<br />

⎣<br />

−4<br />

−6<br />

2<br />

−12<br />

⎤<br />

⎥<br />

⎦ .<br />

=<br />

=<br />

⎡<br />

⎢<br />

⎣<br />

⎡<br />

⎢<br />

⎣<br />

4<br />

4<br />

0<br />

−2<br />

−4<br />

−6<br />

2<br />

−12<br />

⎤ ⎡<br />

⎥<br />

⎦ − 2 ⎢<br />

⎣<br />

⎤<br />

⎥<br />

⎦<br />

4<br />

5<br />

−1<br />

5<br />

⎤<br />

⎥<br />

⎦<br />

4<br />

0<br />

5<br />

⎤⎞<br />

⎦⎠<br />

♠<br />

Suppose two l<strong>in</strong>ear transformations act <strong>in</strong> the same way on ⃗x for all vectors. Then we say that these<br />

transformations are equal.<br />

Def<strong>in</strong>ition 5.15: Equal Transformations<br />

Let S and T be l<strong>in</strong>ear transformations from R n to R m .ThenS = T if and only if for every⃗x ∈ R n ,<br />

S(⃗x)=T (⃗x)<br />

Suppose two l<strong>in</strong>ear transformations act on the same vector ⃗x, first the transformation T andthena<br />

second transformation given by S. Wecanf<strong>in</strong>dthecomposite transformation that results from apply<strong>in</strong>g<br />

both transformations.

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