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A First Course in Linear Algebra, 2017a

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466 Vector Spaces<br />

Def<strong>in</strong>ition 9.12: L<strong>in</strong>ear Comb<strong>in</strong>ation<br />

Let V beavectorspaceandlet{⃗v 1 ,⃗v 2 ,···,⃗v n }⊆V. A vector ⃗v ∈ V is called a l<strong>in</strong>ear comb<strong>in</strong>ation<br />

of the⃗v i if there exist scalars c i ∈ R such that<br />

⃗v = c 1 ⃗v 1 + c 2 ⃗v 2 + ···+ c n ⃗v n<br />

This def<strong>in</strong>ition leads to our next concept of span.<br />

Def<strong>in</strong>ition 9.13: Span of Vectors<br />

Let {⃗v 1 ,···,⃗v n }⊆V. Then<br />

span{⃗v 1 ,···,⃗v n } =<br />

{ n∑<br />

c i ⃗v i : c i ∈ R<br />

i=1<br />

}<br />

When we say that a vector ⃗w is <strong>in</strong> span{⃗v 1 ,···,⃗v n } we mean that ⃗w can be written as a l<strong>in</strong>ear comb<strong>in</strong>ation<br />

of the ⃗v i . We say that a collection of vectors {⃗v 1 ,···,⃗v n } is a spann<strong>in</strong>g set for V if V =<br />

span{⃗v 1 ,···,⃗v n }.<br />

Consider the follow<strong>in</strong>g example.<br />

Example 9.14: Matrix Span<br />

[ ] [ 1 0 0 1<br />

Let A = , B =<br />

0 2 1 0<br />

]<br />

.Determ<strong>in</strong>eifA and B are <strong>in</strong><br />

{[<br />

1 0<br />

span{M 1 ,M 2 } = span<br />

0 0<br />

] [<br />

0 0<br />

,<br />

0 1<br />

]}<br />

Solution.<br />

<strong>First</strong> consider A. We want to see if scalars s,t can be found such that A = sM 1 +tM 2 .<br />

[ ] [ ] [ ]<br />

1 0 1 0 0 0<br />

= s +t<br />

0 2 0 0 0 1<br />

The solution to this equation is given by<br />

1 = s<br />

2 = t<br />

and it follows that A is <strong>in</strong> span{M 1 ,M 2 }.<br />

Now consider B. Aga<strong>in</strong> we write B = sM 1 +tM 2 and see if a solution can be found for s,t.<br />

[ ] [ ] [ ]<br />

0 1 1 0 0 0<br />

= s +t<br />

1 0 0 0 0 1

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