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A First Course in Linear Algebra, 2017a

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4 Systems of Equations<br />

Example 1.1: A Graphical Solution<br />

Use a graph to f<strong>in</strong>d the solution to the follow<strong>in</strong>g system of equations<br />

x + y = 3<br />

y − x = 5<br />

Solution. Through graph<strong>in</strong>g the above equations and identify<strong>in</strong>g the po<strong>in</strong>t of <strong>in</strong>tersection, we can f<strong>in</strong>d the<br />

solution(s). Remember that we must have either one solution, <strong>in</strong>f<strong>in</strong>itely many, or no solutions at all. The<br />

follow<strong>in</strong>g graph shows the two equations, as well as the <strong>in</strong>tersection. Remember, the po<strong>in</strong>t of <strong>in</strong>tersection<br />

represents the solution of the two equations, or the (x,y) which satisfy both equations. In this case, there<br />

is one po<strong>in</strong>t of <strong>in</strong>tersection at (−1,4) which means we have one unique solution, x = −1,y = 4.<br />

6<br />

y<br />

(x,y)=(−1,4)<br />

4<br />

2<br />

−4 −3 −2 −1 1<br />

x<br />

In the above example, we <strong>in</strong>vestigated the <strong>in</strong>tersection po<strong>in</strong>t of two equations <strong>in</strong> two variables, x and<br />

y. Now we will consider the graphical solutions of three equations <strong>in</strong> two variables.<br />

Consider a system of three equations <strong>in</strong> two variables. Aga<strong>in</strong>, these equations can be graphed as<br />

straight l<strong>in</strong>es <strong>in</strong> the plane, so that the result<strong>in</strong>g graph conta<strong>in</strong>s three straight l<strong>in</strong>es. Recall the three possible<br />

types of solutions; no solution, one solution, and <strong>in</strong>f<strong>in</strong>itely many solutions. There are now more complex<br />

ways of achiev<strong>in</strong>g these situations, due to the presence of the third l<strong>in</strong>e. For example, you can imag<strong>in</strong>e<br />

the case of three <strong>in</strong>tersect<strong>in</strong>g l<strong>in</strong>es hav<strong>in</strong>g no common po<strong>in</strong>t of <strong>in</strong>tersection. Perhaps you can also imag<strong>in</strong>e<br />

three <strong>in</strong>tersect<strong>in</strong>g l<strong>in</strong>es which do <strong>in</strong>tersect at a s<strong>in</strong>gle po<strong>in</strong>t. These two situations are illustrated below.<br />

♠<br />

y<br />

y<br />

x<br />

No Solution<br />

x<br />

One Solution

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