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A First Course in Linear Algebra, 2017a

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414 Spectral Theory<br />

The Cholesky Factorization<br />

Another important theorem is the existence of a specific factorization of positive def<strong>in</strong>ite matrices. It is<br />

called the Cholesky Factorization and factors the matrix <strong>in</strong>to the product of an upper triangular matrix and<br />

its transpose.<br />

Theorem 7.79: Cholesky Factorization<br />

Let A be a positive def<strong>in</strong>ite matrix. Then there exists an upper triangular matrix U whose ma<strong>in</strong><br />

diagonal entries are positive, such that A can be written<br />

This factorization is unique.<br />

A = U T U<br />

The process for f<strong>in</strong>d<strong>in</strong>g such a matrix U relies on simple row operations.<br />

Procedure 7.80: F<strong>in</strong>d<strong>in</strong>g the Cholesky Factorization<br />

Let A be a positive def<strong>in</strong>ite matrix. The matrix U that creates the Cholesky Factorization can be<br />

found through two steps.<br />

1. Us<strong>in</strong>g only type 3 elementary row operations (multiples of rows added to other rows) put A <strong>in</strong><br />

upper triangular form. Call this matrix Û. ThenÛ has positive entries on the ma<strong>in</strong> diagonal.<br />

2. Divide each row of Û by the square root of the diagonal entry <strong>in</strong> that row. The result is the<br />

matrix U.<br />

Of course you can always verify that your factorization is correct by multiply<strong>in</strong>g U and U T to ensure<br />

the result is the orig<strong>in</strong>al matrix A.<br />

Consider the follow<strong>in</strong>g example.<br />

Example 7.81: Cholesky Factorization<br />

⎡<br />

9 −6<br />

⎤<br />

3<br />

Show that A = ⎣ −6 5 −3 ⎦ is positive def<strong>in</strong>ite, and f<strong>in</strong>d the Cholesky factorization of A.<br />

3 −3 6<br />

Solution. <strong>First</strong> we show that A is positive def<strong>in</strong>ite. By Theorem 7.77 it suffices to show that the determ<strong>in</strong>ant<br />

of each submatrix is positive.<br />

A 1 = [ 9 ] [ ]<br />

9 −6<br />

and A 2 =<br />

,<br />

−6 5<br />

so det(A 1 )=9 and det(A 2 )=9. S<strong>in</strong>ce det(A)=36, it follows that A is positive def<strong>in</strong>ite.<br />

Now we use Procedure 7.80 to f<strong>in</strong>d the Cholesky Factorization. Row reduce (us<strong>in</strong>g only type 3 row

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