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Fighter Combat - Tactics and Maneuvering

Fighter Combat - Tactics and Maneuvering

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TACTICAL INTERCEPTS 351<br />

interceptor's nose is pointed directly at the target through most of the turn<br />

to minimize the area of the fighter that is visible to the bogey pilot. The<br />

interceptor pilot needs a rough idea of the amount of displacement that is<br />

required. Having gained this displacement, the interceptor pilot must<br />

know at what target range, or conversion range, the intended conversion<br />

turn will bring the interceptor behind the bogey at the desired trail position.<br />

Taken together, the desired displacement <strong>and</strong> the conversion range<br />

define the "conversion point," which is the interceptor pilot's initial goal.<br />

Assume for this example that the conversion range is 8 nautical miles<br />

(8 NM) with 20,000 ft displacement. At time "I" the target is 30 NM away<br />

<strong>and</strong> the interceptor's radar weapons system computes about 2° of target<br />

aspect. With a little mental gymnastics the interceptor pilot can estimate<br />

his displacement using the formula:<br />

100 x TAA (degrees) x Range (NM) = Displacement (ft).<br />

In this case, 100 x 2° x 30 NM = 6,000 ft, so more displacement is<br />

required. (Some weapons systems also compute this displacement for the<br />

pilot.) The interceptor pilot, therefore, takes a cut away from the bogey's<br />

flight path, being careful not to turn so far that his radar antenna gimbal<br />

limits are exceeded. The actual magnitude of this displacement turn<br />

should be great enough to generate the required displacement prior to the<br />

conversion range.<br />

Between times " 1" <strong>and</strong> "2" the interceptor pilot continuously monitors<br />

range, TAA, <strong>and</strong> displacement. At 20 NM range, aspect is determined to be<br />

about 10°, yielding the desired 20,000 ft displacement. Now the interceptor<br />

must maintain that displacement until conversion range (8 NM). To<br />

achieve this the interceptor turns to parallel the bogey's course at time<br />

"2," <strong>and</strong> simply drives in to 8 NM range, time "3." At this point the<br />

conversion turn is commenced <strong>and</strong> results in the interceptor rolling out at<br />

the desired distance behind the target. This distance is generally planned<br />

to be in the heart of the interceptor's RQ weapons-firing envelope. When<br />

this weapons range is short, such as for guns, much care must be exercised<br />

in the final stages of the conversion turn to avoid overshooting the bogey's<br />

flight path at close range.<br />

The conversion range for this intercept is predicated primarily on the<br />

time required for the interceptor to complete its conversion turn. This<br />

time determines the interceptor's final roll-out distance behind the target.<br />

Figure 10-3. Stern-Conversion Intercept

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