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A4-format til udskrift. - Aarhus Universitet

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26 I. DIFFERENTIATION<br />

En ligning for tangentlinjen er<br />

y − b = f ′ (a)(x − a)<br />

3.4. Find tangentlinjen ☞ [S] 2.7 Derivatives<br />

Eksempel 2<br />

Find ligningen for tangentlinjen <strong>til</strong> y = x 2 − 8x + 9 i punktet (3, −6).<br />

Den afledede er<br />

y ′ = 2x − 8, y ′ (3) = −2<br />

Ligningen for tangentlinjen er<br />

eller<br />

y − (−6) = (−2)(x − 3)<br />

y = −2x<br />

3.5. Tangentplan ☞ [S] 11.4 Tangent planes and linear approximations<br />

Figur<br />

y<br />

0<br />

D<br />

(x,y)<br />

x<br />

D ⊂ R 2 , f : D → R<br />

f(x,y)<br />

3.6. Tangentplan ☞ [S] 11.4 Tangent planes and linear approx.<br />

Definition<br />

Tangentplanen <strong>til</strong> grafen for en funktion z = f(x,y) i et punkt (x0,y0,z0), z0 = f(x0,y0)<br />

er planen gennem (x0,y0,z0), som indeholder tangentvektorerne<br />

<strong>til</strong> koordinatkurverne<br />

på grafen Γf .<br />

(1,0,fx(x0,y0)), (0,1,fy(x0,y0))<br />

x ↦→ (x,y0,f(x,y0)), y ↦→ (x0,y,f(x0,y))<br />

3.7. Ligning for tangentplan ☞ [S] 11.4 Tangent planes and linear approx.<br />

2 Sætning<br />

Antag at f har kontinuerte partielle afledede fx,fy i en lille cirkelskive om (x0,y0). Tangentplanen<br />

for grafen i et punkt (x0,y0,z0), z0 = f(x0,y0) har ligning<br />

Bevis<br />

z − z0 = fx(x0,y0)(x − x0) + fy(x0,y0)(y − y0)

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